The projectile's horizontal and vertical positions at time
are given by


where
. Solve
for the time
it takes for the projectile to reach the ground:

In this time, the projectile will have traveled horizontally a distance of

The projectile's horizontal and vertical velocities are given by


At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about
.
Answer:
Step-by-step explanation:
Q1
<u>Angles</u>
- 26° & 64° & 90°
- AA similarity
Q2
<u>Ratios of corresponding sides:</u>
- 6/8 = 9/12 = 12/16 ⇒ 3/4
- SSS similarity
Q3
<u>Angle C is vertical</u>
<u>Ratios of corresponding sides:</u>
- 9/15 = 18/30 ⇒ 3/5
- SAS similarity
45x to the 3rd power y divided by 9xy
5x to the 3rd power y
Answer:
27 1/7
Step-by-step explanation:
Multiply 5×5=25 and afterwards multiply 3/7×5=2 1/7
The area would be 30. it would be 6x5