Do You have a pictures of the Cylinders? it would help alot
The number of the atom would be half the numbers that is there
Answer:
grams
Explanation:
Complete question is
You are asked to pre pare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid
(C6H5COOH)
and any amount you need of sodium benzoate
(C6H5COONa)
How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.
Solution
Given
pH of the buffer solution
Concentration of C6H5COOH M
Volume of the buffer solution L
value for benzoic acid is
Concentration of sodium benzoate
Substituting the given values we get
Number of moles in sodium benzoate
Mass of sodium benzoate
Answer:
Mass of water = 41.8 g
Explanation:
Given data:
Mass of water = ?
Change in temperature = 3.0 °C
Specific heat capacity = 4.184 j/g.°C
Heat absorbed = 525 j
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 3.0°C
Now we will put the values in formula.
525 J = m × 4.184 j/g.°C × 3.0°C
525 J = m × 12.552 j/g
m = 525 J/ 12.552 j/g
m = 41.8 g