Answer:
B. The [H1+] >[OH1-] and the solution is acidic
Answer:
K= -0.286 Mol^-1.S^-1
Explanation:
FIRSTLY, WE WRITE A CHEMICAL REACTION EQUATION FOR THE REACTION BETWEEN OXALIC ACID AND POTASSIUM PERMANGANATE.
KMnO2(aq) + H2C2O4(aq) ----> Mn2+(aq) + CO2(g) + H2O(l)
(purple) (colorless)
THE RATE OF THE REACTION IS MEASURED AND MONITORED BY CHECKING FOR THE DISAPPEARANCE OF THE PURPLE COLOR OF THE POTASSIUM PERMANGANATE.
The rate of the reaction is given by : -Δ[KMnO4]/ΔT = -Δ[ H2C2O4]/ΔT = Δ[ Mn2+]/ΔT
When all of the purple color is gone, we can say that the reaction is finished and that the final concentration of the KMnO4 is now zero. Since the initial time for ΔT is zero, the equation for the rate of
disappearance of the potassium permanganate becomes:
Rate = Δ[KMnO4]/ΔT= (0-[initial KMnO4]) ÷ (elapsed time -0) = [Initial KMnO4 ] ÷ elapsed time
Hence, the rate of the chemical reaction is thus;
-1.3/5 = -0.26M/s
Now, to get the rate constant for the reaction, we need to know the rate law and this can be expressed as follows:
For a reaction A+B---> C The general rate law would be: Rate = k[A]^m[B]^n
In this particular case,
Rate =k [KMnO4][ H2C2O4]
Kindly note that m and n in this case is 1 each. We have calculated our rate from above. Hence:
-0.26 = k(1.3)(0.7)
k = -0.26÷(1.3)(0.7)
K= -0.286 Mol^-1.S^-1
Answer:
Mass = 17.8 g
Explanation:
Given data:
Number of atoms of Ca = 2.68 × 10²³
Mass in gram = ?
Solution:
Avogadro number:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ atoms
2.68 × 10²³ atoms × 1 mole /6.022 × 10²³ atoms
0.445 mol
Mass in gram;
Mass = number of moles × molar mass
Mass = 0.445 mol × 40 g/mol
Mass = 17.8 g
Answer:
94448421.2201
Explanation:
multiply the value in kilometers by the conversion factor '0.62137119223684'.
So, 152000 kilometers = 152000 × 0.62137119223684 = 94448.42122 miles.