The given formula for heat, Q=mc(Tf-Ti), is the best way to solve such problems with changes in temperature. It can be said that m is the mass of the substance. C is the specific heat of the substance. The term (Tf-Ti) is the change in temperature.
Q = mc(Tf-Ti) = 480g(0.96 J/g-C)(234-22) = 97689.6 Joules of heat
Answer:
The answer to your question is 0.5 moles
Explanation:
Data
moles of Glucose = ?
moles of carbon dioxide = 3
Balanced chemical reaction
6CO₂ + 6H₂O ⇒ C₆H₁₂O₆ + 6O₂
Process
To solve this problem, use proportions, and cross multiplication.
Use the coefficients of the balanced equation.
6 moles of CO₂ ----------------- 1 mol of C₆H₁₂O₆
3 moles of CO₂ ---------------- x
x = (3 x 1) / 6
-Simplification
x = 3/6
-Result
x = 0.5 moles of Glucose
When all the electrons are placed in their orbitals!!!
Answer: 625 grams
Explanation:
14 goes into 56, 4 times.
10,000÷2=5,000 - first half life
5,000÷2=2,500 - second half life
2,500÷2=1,250 - 3rd half life
1,250÷2= 625 - 4th half life
Note: don't type "grams" after 625, just type "625".
