The equation is as follows;
2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2×82.3)/252.3
= 0.6524 moles
which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g
Hi,
your answer would be false. But it seems you already knew that.
I hoped I helped and if you need help you could always ask me :)
-Dawn
The answer to your question is ( Protons and neautrons)
is this supposed to sound like an actual question? it looks like something computer generated to me, but, yes?
