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Ivenika [448]
3 years ago
5

What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
8 0
Data:

m (<span>Sample Mass) = ? 
n (</span><span>Number of moles) = 0.714 mol
MM (Molar Mass) of </span>Mercury (I) Chloride (Hg_{2}  Cl_{2})
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass Hg_{2} Cl_{2} = 401.18 + 70.906 = 472.086 ≈ 472.09<span> amu or 472.09 g/mol
</span>
Formula:

n =  \frac{m}{MM}

Solving:


n = \frac{m}{MM}
0.714 =  \frac{m}{472.09}
m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark

Answer:
By approximation would be letter D) <span>337.2 g</span>


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Explanation:

A balanced chemical reaction follows law of conservation of mass.

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Single displacement reaction is defined as the reaction in which more reactive metal displaces a less reactive metal from its chemical reaction.

General equation representing single displacement reaction follows:

AB+C\rightarrow CB+A

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The reactivity of metals is judged by the series known as reactivity series. Elements lying above in the series are more reactive than the elements lying below in the series.

  • 1. When solid lead metal is put in the beaker of 0.043 M Fe(NO_3)_2 solution.

Lead lies below in the reactivity series than iron. Thus, it will not replace iron from its chemical reaction.

Pb(s)+Fe(NO_3)_2(aq.)\rightarrow \text{No reaction}

  • 2. When solid iron metal is put in the beaker of 0.044 M Pb(NO_3)_2 solution.

Iron lies above in the reactivity series than lead. Thus, it will easily replace lead from its chemical reaction.

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6 0
3 years ago
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Answer:

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B. 0.6 mole of Cu2S

Explanation:

A. The balancing equation.

The equation can be balance as follow:

CuCl + H2S —> Cu2S + HCl

There are 2 atoms of Cu on the right side and 1 atom on the left. It can be balance by putting 2 in front of CuCl as shown below:

2CuCl + H2S —> Cu2S + HCl

There are 2 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 2 in front of HCl as shown below:

2CuCl + H2S —> Cu2S + 2HCl

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This is illustrated below:

2CuCl + H2S —> Cu2S + 2HCl

From the balanced equation above, 2 moles of CuCl reacted to produce 1 mole of Cu2S.

Therefore, 1.2 mole of CuCl will react to produce = 1.2/2 = 0.6 mole of Cu2S.

Therefore, 0.6 mole of Cu2S is produced from the reaction of 1.2 mole of CuCl.

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4 years ago
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