Question

What is the mass of 0.714 moles of Mercury (I) Chloride (Hg2Cl2)?

Answer 1

Data:

m (Sample Mass) = ? 
n (Number of moles) = 0.714 mol
MM (Molar Mass) of Mercury (I) Chloride ($Hg_{2} Cl_{2}$)
Hg = 2*200.59 = 401.18 amu
Cl = 2*35.453 = 70.906 amu
----------------------------------------
Molar Mass $Hg_{2} Cl_{2}$ = 401.18 + 70.906 = 472.086 ≈ 472.09 amu or 472.09 g/mol

Formula:

$n = \frac{m}{MM}$

Solving:


$n = \frac{m}{MM}$
$0.714 = \frac{m}{472.09}$
$m = 337.07226\:\to\:\boxed{\boxed{m\approx 337 g}} \end{array}}\qquad\quad\checkmark$

Answer:
By approximation would be letter D) 337.2 g