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frutty [35]
3 years ago
12

73.5 grams C, 4.20 grams H, and 72.3 grams Cl. What is the percent composition of each element in this compound?

Chemistry
1 answer:
Umnica [9.8K]3 years ago
6 0
To find percent composition do "parts over the whole" ---> each individual mass over the total mass times 100 (since it is a percentage). 

total mass ("the whole")= 73.5 + 42.0 + 72.3 grams= 150 grams

1. Carbon %= 73.5 grams/ 150 grams x 100= 49.0%

2. Hydrogen %= 4.20 grams/ 150 grams x 100= 2.80%

3. Chlorine %= 72.3 grams/ 150 grams x 100= 48.2%
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What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t
const2013 [10]

Answer:

C = 0.08M

Explanation:

molar mass of AlCl3

Al =27

Cl = 35.5

27+3(35.5) =133.5g/mol

n= mass/Molar mass

n =CV

CV = mass/molar mass

C x 500 x 10^-³ = 5/133.5

C x 500 x 10^-³ = 0.04

C = 0.04/500 x 10^-³

C = 0.08M

4 0
3 years ago
If pure water boils at 99.8 degrees celcius, what is the expected elevated boiling point of a solution of 2.50g of CaCl2, in 50.
Alexeev081 [22]

INFORMATION:

We know that:

- pure water boils at 99.8 degrees celcius

And we must calculate the expected elevated boiling point of a solution of 2.50g of CaCl2, in 50.0mL (i.e., 50.0g) of H2O

STEP BY STEP EXPLANATION:

To calculate it, we need to use that:

Boiling point of solution = boiling point of pure solvent + boiling point elevation (ΔTb)

The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation.

ΔTb=i\times k_b\times m

Where,

- i is the Van’t Hoff factor

- Kb is the ebullioscopic constant

- m is the molality of the solute

From given information, we know that:

- i = 3

Now, the ebullioscopic constant (Kb) is often expressed in terms of °C * kg * mol^-1. The value of Kb for water is 0.512.

So, kb = 0.512 °C * kg * mol^-1

Then, we must calculate the molality

\begin{gathered} Molality=\frac{\text{ moles of solute}}{\text{ kg of solvent}} \\ Molality=\frac{\frac{2.5g}{110.98\frac{g}{mol}}}{0.05kg}=0.45\frac{mol}{kg} \end{gathered}

So, m = 0.45 mol/kg

Replacing the values in the formula for ΔTb

\begin{gathered} ΔT_b=3\times0.512\frac{\degree C\cdot kg}{mol}\times0.45\frac{mol}{kg} \\ ΔT_b=0.69\degree C \end{gathered}

Finally, the expected elevated boiling point of the solution would be

\text{ Boling point of solution}=99.8\degree C+0.69\degree C=100.49\degree C

ANSWER:

The expected elevated boiling point of the solution is 100.49 °C

3 0
1 year ago
I WILL GIVE BRAINLIEST
juin [17]

Answer:

Volumes can have the same volume but different masses if they have different densities. For example, a 10 x 10 x 10 block of lead has the same volume as a 10 x 10 x 10 block of pine wood, but the lead block weighs 22.6 times more than the pine block. Indeed, the density of lead is high enough that the lead block will sink in water, whereas the pine block's density is low enough that the pine block will float in water.

Volume is a measurement, the units are cubic metres or cubic centimetres. Litres = 1000 cm3

Mass is a measurement, the units are grams, kilograms.

^^^^^^^^^^^^^^^^^^

to that answer.

Mass is not weight. it is the amount of matter an object takes up. Therefore, saying that a lead block weights 22.6 times more than the pine block does not answer how an object can have different masses but the same volume. :D

5 0
3 years ago
Which of the foods did you determine to be nutritious snacks?
Goshia [24]
Fruits and vegetables
3 0
3 years ago
can we stir silver nitrate solution with copper spoon? why or why not? support your answer with reason.​
HACTEHA [7]

↪ Hello miss "galaxyu035" here's your answer for the question you wrote.

Answer :

No, <u>we cannot</u> stir silver nitrate solution with a copper spoon <u>because</u> , copper is more reactive than silver. Thus,it would displace silver from the silver nitrate solution forming copper nitrate.

---

Remember if my answer helps you! Might give me a thank you! By clicking the heart button .

8 0
3 years ago
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