Answer: Keq= [CO2]^6[H2O]^6/ [O2]^6
Explanation:
Answer:
4.81×10¹⁰ atoms.
Explanation:
We'll begin by converting 3.2 pg to Ca to grams (g). This can be obtained as follow:
1 pg = 1×10¯¹² g
Therefore,
3.2 pg = 3.2 pg × 1×10¯¹² g / 1 pg
3.2 pg = 3.2×10¯¹² g
Therefore, 3.2 pg is equivalent to 3.2×10¯¹² g
Next, we shall determine the number of mole in 3.2×10¯¹² g of Ca. This can be obtained as follow:
Mass of Ca = 3.2×10¯¹² g
Molar mass of Ca = 40.08 g/mol
Mole of ca=.?
Mole = mass /molar mass
Mole of Ca = 3.2×10¯¹² / 40.08
Mole of Ca = 7.98×10¯¹⁴ mole.
Finally, we shall determine the number of atoms present in 7.98×10¯¹⁴ mole of Ca. This can be obtained as illustrated below:
From Avogadro's hypothesis,
1 mole of Ca contains 6.02×10²³ atoms.
Therefore, 7.98×10¯¹⁴ mole of Ca will contain = 7.98×10¯¹⁴ × 6.02×10²³ = 4.81×10¹⁰ atoms.
Therefore, 3.2 pg of Ca contains 4.81×10¹⁰ atoms.
Answer:
A. 1.63g/dm^3 (3 s.f.)
B. 0.833g/dm^3 (3 s.f.)
C. 1.92g/dm^3 (3 s.f.)
Explanation:
Please see attached picture for full solution.
Positive ions are atoms that have lost an electron from its outtermost shell. It is positive because electrons are negative and the loss of something negative makes it a bit more positive.
A negative ion is larger than its original atom because it's gained an electron.
The more electrons an atomic has on its electron cloud, the bigger the atom.
Hopefully I didn't confuse you, good luck. ♡
Ununoctium, also known as eka-radon.
hope this helps!
