Do you mean <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x+5<span>cos3</span>x+10cosx</span></span> ?</span>
or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x+5cos3x+10cosx</span></span> ?</span>
or <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x</span></span>+5<span>cos3</span>x+10cosx ?</span>
or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x</span></span>+5cos3x+10cosx <span>?</span></span>
Answer:
the conditional probability that X = 1 , X = 2 and X = 3 is 0.7333 (73.33%) , 0.25 (25%) and 0.0167 (1.67%) respectively
Step-by-step explanation:
a player wins money when i>0 then defining event W= gain money , then
P(W) = p(i>0) = p(1)+p(2)+p(3)
then the conditional probability can be calculated through the theorem of Bayes
P(X=1/W)= P(X=1 ∩ W)/P(W)
where
P(X=1 ∩ W)= probability that the payout is 1 and earns money
P(X=1 / W)= probability that the payout is 1 given money was earned
then
P(X=1/W)= P(X=1 ∩ W)/P(W) = P(X=1) / P(W) = p(1) /[p(1)+p(2)+p(3)] = 11/40 /(11/40+3/32+1/160
) = 0.7333 (73.33%)
similarly
P(X=2/W)=p(2) /[p(1)+p(2)+p(3)] = 3/32 /(11/40+3/32+1/160
) = 0.25 (25%)
P(X=3/W)=p(2) /[p(1)+p(2)+p(3)] = 1/160 /(11/40+3/32+1/160
) = 0.0167 (1.67%)
Answer: x >= -(5/3)
Step-by-step explanation:
Answer:
y = -2(W - x + 2)
Step-by-step explanation:
W=x-y/2- 2
W - x + 2 = - y/2
-2(W - x + 2) = y
22=-11k is K= -2 hope this helps
