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Ad libitum [116K]
2 years ago
5

How many grams of aluminum phosphate is produced from 7.5 g of lithium phosphate in this balanced equation? 2Li3PO4 + Al2(SO4)3

= 3Li2SO4 + 2AlPO4
Chemistry
1 answer:
iren [92.7K]2 years ago
4 0

7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.

<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

2Li_3PO_4 + Al_2(SO_4)_3→ 3Li_2SO_4 + 2AlPO_4

Moles of 7.5 g of lithium phosphate.

The molar mass of lithium phosphate is 115.79 g/mol.

Moles = \frac{mass}{molar \;mass}

Moles =\frac{7.5 g}{115.79 g/mol}

Moles = \frac{7.5 g}{115.79 g/mol}

Moles = 0.06477243285

Now we will compare the moles of AlPO_4 with Li_3PO_4.

               Li_3PO_4               :     AlPO_4

                   2            :               2

                0.385       :              2÷2× 0.064 = 0.064 mol

Mass of AlPO_4 :

Mass of AlPO_4 = moles × molar mass

Mass of AlPO_4 =0.064  mol × 121.9529 g/mol

Mass of AlPO_4 =  7.8049856 g

Hence, 7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

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