Question

How many grams of aluminum phosphate is produced from 7.5 g of lithium phosphate in this balanced equation? 2Li3PO4 + Al2(SO4)3 = 3Li2SO4 + 2AlPO4

Answer 1

7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.

What are moles?

A mole is defined as 6.02214076 × $10^{23}$ of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

$2Li_3PO_4 + Al_2(SO_4)_3$→ $3Li_2SO_4 + 2AlPO_4$

Moles of 7.5 g of lithium phosphate.

The molar mass of lithium phosphate is 115.79 g/mol.

Moles = $\frac{mass}{molar \;mass}$

Moles =$\frac{7.5 g}{115.79 g/mol}$

Moles = $\frac{7.5 g}{115.79 g/mol}$

Moles = 0.06477243285

Now we will compare the moles of $AlPO_4$ with $Li_3PO_4$.

               $Li_3PO_4$               :     $AlPO_4$

                   2            :               2

                0.385       :              2÷2× 0.064 = 0.064 mol

Mass of $AlPO_4$ :

Mass of $AlPO_4$ = moles × molar mass

Mass of $AlPO_4$ =0.064  mol × 121.9529 g/mol

Mass of $AlPO_4$ =  7.8049856 g

Hence, 7.8049856 g of aluminium phosphate is produced from 7.5 g of lithium phosphate in this balanced equation.

Learn more about moles here:

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