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3 years ago

Analysis/Conclusions:

Chemistry

2 answers:

Naya [18.7K]3 years ago

8 0

1. MgSO4+2NH4OH=(NH4)2SO4+Mg(OH)2

Paha777 [63]3 years ago

5 0

The correct answers are as follows:
1. MgSO4 + 2NH4OH = [NH4]2SO4 + Mg[OH]2.
This chemical equation implies that, one molecule of magnesium sulphate react with two molecules of ammonium hydroxide to give rise to one molecule of ammonium sulphate and one molecule of magnesium hydroxide.
2. The reaction between magnesium sulphate and ammonia is a DOUBLE REPLACEMENT REACTION.
A double replacement reaction is a type of reaction in which the two chemical substances which take part in the reaction switch their ions in such a way that two new products are formed. In the reaction of magnesium sulphate and ammonia, the magnesium sulphate gives its SO4 ion to ammonia and take the OH ion of the ammonia instead.
3. The epsom salt and the ammonia reacted. This is made obvious by the chemical reaction which was generated by their combination. On the edge of the penny used, one can see that there is a colour change, this shows that a chemical reaction occur.

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Acetic acid has a pKa of 4.74. Buffer A: 0.10 M HC2H3O2, 0.10 M NaC2H3O2 Buffer B: 0.30 M HC2H3O2, 0.30 M NaC2H3O2 Buffer C: 0.5

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Buffer B has the highest buffer capacity.

Buffer C has the lowest buffer capacity.

Explanation:

An effective weak acid-conjugate base buffer should have pH equal to $pK_{a}$ of the weak acid. For buffers with the same pH, higher the concentrations of the components in a buffer, higher will the buffer capacity.

Acetic acid is a weak acid and $CH_{3}COO^{-}$ is the conjugate base So, all the given buffers are weak acid-conjugate base buffers. The pH of these buffers are expressed as (Henderson-Hasselbalch):

$pH=pK_{a}(CH_{3}COOH)+log\frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}$

$pK_{a}(CH_{3}COOH)=4.74$

Buffer A: $pH=4.74+log(\frac{0.10}{0.10})=4.74$

Buffer B: $pH=4.74+log(\frac{0.30}{0.30})=4.74$

Buffer C: $pH=4.74+log(\frac{0.10}{0.50})=4.04$

So, both buffer A and buffer B has same pH value which is also equal to $pK_{a}$ . Buffer B has higher concentrations of the components as compared to buffer A, Hence, buffer B has the highest buffer capacity.

The pH of buffer C is far away from $pK_{a}$ . Therefore, buffer C has the lowest buffer capacity.

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