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spayn [35]
4 years ago
15

Analysis/Conclusions:

Chemistry
2 answers:
Naya [18.7K]4 years ago
8 0
1. MgSO4+2NH4OH=(NH4)2SO4+Mg(OH)2
Paha777 [63]4 years ago
5 0
The correct answers are as follows:
1. MgSO4 + 2NH4OH = [NH4]2SO4 + Mg[OH]2.
This chemical equation implies that, one molecule of magnesium sulphate react with two molecules of ammonium hydroxide to give rise to one molecule of ammonium sulphate and  one molecule of magnesium hydroxide. 
2. The reaction between magnesium sulphate and ammonia is a DOUBLE REPLACEMENT REACTION.
A double replacement reaction is a type of reaction in which the two chemical substances which take part in the reaction switch their ions in such a way that two new products are formed. In the reaction of magnesium sulphate and ammonia, the magnesium sulphate gives its SO4 ion to ammonia and take the OH ion of the ammonia instead. 
3. The epsom salt and the ammonia reacted. This is made obvious by the chemical reaction which was generated by their combination. On the edge of the penny used, one can see that there is a colour change, this shows that a chemical reaction occur.
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Ugo [173]
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4 0
3 years ago
Read 2 more answers
Need help ASAP with this question
Karo-lina-s [1.5K]

Answer: noble gasses

Explanation: zoom on on the red section and look at the key for what red means.

8 0
3 years ago
What is the molarity of a hydrochloric acid solution, when 30.0 mL is neutralized by 48.0 mL of 0.100 mol/L
bulgar [2K]

The molarity of a hydrochloric acid solution : 0.32 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution).

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.  

Acid-base titration formula  

Ma. Va. na = Mb. Vb. nb  

Ma, Mb = acid base concentration  

Va, Vb = acid base volume  

na, nb = acid base valence  

1 ⇒HCl (valence=1, HCl ⇒H⁺+Cl⁻, one H⁺)

2⇒Ca(OH)₂(valence=2, Ca(OH)₂⇒Ca²⁺+2OH⁻, two OH⁻)

M₂=0.1 M

V₂=48 ml=0.048 L

V₁=30 ml=0.03 L

\tt M_1.V_1.n_1=M_2.V_2.n_2\\\\M_1\times 0.03\times 1=0.1\times 0.048\times 2\\\\M_1=0.32

3 0
3 years ago
An unknown compound has the following chemical formula: Mg_xCl_2
Art [367]

Answer:

Explanation:

Given parameters:

number of moles magnesium = 6.80mol

number of moles of chlorine = 13.56mol

To find the complete chemical formula, we should obtain the formula of the compound.

                                Mg                            Cl

Number of

moles                      6.8                           13.56

Dividing

by the smallest      6.8/6.8                    13.56/6.8

                                    1                                2

  The formula of the compound is MgCl₂

This is an ionic compound in which Magnesium loses two electrons that would be gained by Cl atoms requiring just an electron each to complete their octet.

3 0
4 years ago
which atom has a change in oxidation number of -3 in the following redox reaction K2Cr2O7 + H2O +S --&gt; KOH + Cr2O3 +SO2
yaroslaw [1]
You have to calculate the oxidation estates of the atoms in each compound.

I will start with K2Cr2O7 because I believe that Cr is the best candidate to reduce its oxidation number in 3 units.

In K2Cr2O7:

- K has oxidation state of 1+, then K2 has a charge of 2* (1+) = 2+.

- O has oxidation state of 2*, then O7 has a charge of 7* (2-) = 14-.

That makes that Cr2 has charge of 14 - 2 = +12, so each Cr has +12/2 = +6 oxidation state.

In Cr2O3:

- O has oxidation state of 2-, then O3 has charge 3 * (2-) = - 6

- Then, Cr2 has charge 6+, and each Cr has charge 6+ / 2 = 3+.

So, we have seen that Cr reduced its oxidation state in 3 units, from 6+ to 3+.

Answer: Cr has a change in oxidation number of - 3.
6 0
3 years ago
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