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Delvig [45]
2 years ago
9

If the clot breaks free and only experiences a force due to the blood pressure, what is the relationship between the pressure on

each side of the clot as it moves with a constant velocity toward the heart
Physics
1 answer:
Bingel [31]2 years ago
6 0

Answer:

The pressure on each side of the clot is same.

Explanation:

The clot is moving with a constant velocity which implies that the total force on the clot is zero.

The force F is given by the formula.

F=ΔPA

where ΔP is the difference in pressure and A is the area.

Since the force is same on either side, therefore,

ΔPA=0

Also, the area is same on both side of the clot.

Therefore the difference in the pressure of both side is zero which implies that the pressure on both sides are equal.

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olga55 [171]

Answer:

Change in momentum, \Delta p=6.3\ kg-m/s

Explanation:

It is given that,

Mass of the basketball, m = 601 g = 0.601 kg

The basketball makes an angle of 29 degrees to the vertical, it hits the floor with a speed, v = 6 m/s

It bounces up with the same speed, again moving to the right at an angle of 29 degree to the vertical. We need to find the change in momentum. It is given by :

\Delta p=mv\ cos\theta-(-mv\ cos\theta)

\Delta p=2mv\ cos\theta

\Delta p=2\times 0.601\times 6\times \ cos(29)

\Delta p=6.3\ kg-m/s

So, the change in momentum of the basketball is 6.3 kg-m/s. Hence, this is the required solution.

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Answer:

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In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

Hence, the temperature or thermal energy of matter depends on how much the particles are moving, which depends on the amount of kinetic energy the particles possess.​

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