1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lys-0071 [83]
3 years ago
15

Which of these people have a stressed induced stomachache

Physics
1 answer:
castortr0y [4]3 years ago
4 0
Molly & Caden have a stressed
You might be interested in
Radioactive isotopes are used in medicine to create images of internal
VMariaS [17]

Answer:

The correct option is D) Fission

Explanation:

There are several methods through which Radioactive isotopes are created.

  1. Using a nuclear reactor that has a field of neutrons, insert a stable sample such as Lutetium-176. When it gets bombarded with neutrons, it acquires some, and fission is said to have occurred. Note that when Lutetium-176 acquires a neutron, it becomes radioactive Lu-177.
  2. Fission is also used to create Fluorine-18. To obtain the same, you need to bombard pure or enriched [^{18} O] water with ~18 MeV protons which are high energy in nature. The bombarding is achieved using a cyclotron or an accelerator.

Cheers

3 0
3 years ago
What is the magnitude of the magnetic dipole moment of the bar magnet
Annette [7]

The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²

<h3> Magnetic dipole moment of the bar magnet</h3>

The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}

where;

  • B is magnetic field
  • m is dipole moment
  • μ is permeability of free space

m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)

m = 1.2 Am²

The complete question is below:

What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.

Learn more about dipole moment here: brainly.com/question/27590192

#SPJ11

6 0
2 years ago
During light activity, a 70-kg person may generate 200 kcal
Lerok [7]

Answer:

2.75387\ ^{\circ}

Explanation:

m = Mass of person = 70 kg

c = Specific heat of human body = 0.83\ J/kg^{\circ}C

\Delta T = Change in temperature

Time taken is 1 hour

Heat is given by

Q=mc\Delta T\\\Rightarrow \Delta T=\dfrac{Q}{mc}\\\Rightarrow \Delta T=\dfrac{0.8\times 200\times 1}{70\times 0.83}\\\Rightarrow \Delta T=2.75387\ ^{\circ}C

The rise in temperature is 2.75387\ ^{\circ}C

3 0
4 years ago
The acceleration of a particle is given by ax(t) = -(2.00 m/s2) + (2.70 m/s3)t. (a) find the initial velocity v0x, such that the
Alexeev081 [22]
I’ll solve them right now just wait a few
3 0
3 years ago
Helpp!!! Will mark brainlst
masya89 [10]

Answer:

i dont know

Explanation:

cuz i dont know what it wrote its too blurry

5 0
3 years ago
Other questions:
  • How can human health be affected by changes in air quality?
    12·1 answer
  • Explain ways that weak and strong nuclear forces are alike.
    13·1 answer
  • Which of these assumptions is Ptolemy's model of planetary motion based on?
    13·2 answers
  • What kind of gas cloud is most likely to give birth to stars? what kind of gas cloud is most likely to give birth to stars? a co
    13·1 answer
  • Particle of the nucleus that has no electrical charge
    12·2 answers
  • If the unbalanced force is -20.0 N and the mass of the object is 3.75 kg, what is the acceleration of the the object while this
    13·1 answer
  • Explain how a thumbtack is designed so that you do not have to use a lot of force to push it through paper or the surface of a b
    11·1 answer
  • In each of two coils the rate of change of the magnetic flux in a single loop is the same. The emf induced in coil 1, which has
    10·1 answer
  • The north pole of magnet A will __?____ the south pole of magnet B
    9·1 answer
  • Please help with a step by step method ​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!