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2 years ago

The normal formula to find force is F = m*a. What kind of math do you need to do

Physics

1 answer:

inessss [21]2 years ago

7 0

$\\ \sf\Rrightarrow F=ma$

Take a to left
As it's multiplied on right side it will be divided on right side.

$\\ \sf\Rrightarrow \dfrac{F}{a}=m$

$\\ \sf\Rrightarrow m=\dfrac{F}{a}$

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Consider an isolated system, by which we mean a system free of external forces. If the sum of the particle energies in the syste

Airida [17]

Answer:

The system's potential energy is -147 J.

Explanation:

Given that,

Energy = 147 J

We know that,

System is isolated and it is free from external forces.

So, the work done by the external forces on the system should be equal to zero.

$W=0$

We need to calculate the system's potential energy

Using thermodynamics first equation

$\Delta U=W-\Delta E$

Put the value into the formula

$\Delta U=0-147$

$\Delta U=-147\ J$

Hence, The system's potential energy is -147 J.

5 0

3 years ago

Car A rear ends Car B, which has twice the mass of A, on an icy road at a speed low enough so that the collision is essentially

mixer [17]

Answer:

D. The momentum of Car B is three times as great in magnitude as that of car A.

Explanation:

I majored in Physics

3 0

3 years ago

Which factor affects the angle of sunlight on Earth? The distance between Earth and the sun Earth's tilt from its axis The path

Rainbow [258]

Earth’s tilt from its axis.
For explanation:
The angle in which Earth is at is 23.5°. This causes its tilt which affects how the Sun’s light hits Earth

6 0

1 year ago

Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc

kumpel [21]

Answer: $\frac{D_A}{v_B-v_A}$

Explanation:

Given

car A had a head start of $D_A$

and it starts at x=0 and t=0

Car B has to travel a distance of $D_A and d_a$

where $d_a$ is the distance travel by car A in time t

distance travel by car A is

$d_a=v_A\times t$

For car B with speed $v_B$

$d_B=D_A+d_a$

$v_B\times t=D_A+v_A\times t$

$t=\frac{D_A}{v_B-v_A}$

7 0

3 years ago

Three forces are applied to a solid cylinder of mass 12 kg (see the drawing). The magnitudes of the forces are F1 = 15 N, F2 = 2

crimeas [40]

Answer:

α = 13.7 rad / s²

Explanation:

Let's use Newton's second law for rotational motion

∑ τ = I α

we will assume that the counterclockwise turns are positive

F₁ 0 + F₂ R₂ - F₃ R₃ = I α

give us the cylinder moment of inertia

I = ½ M R₂²

α = (F₂ R₂ - F₃ R₃) $\frac{2}{M R_2^2}$

let's calculate

α = (24 0.22 - 13 0.10) $\frac{2}{12 \ 0.22^2}$ 2/12 0.22²

α = 13.7 rad / s²

6 0

3 years ago