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Paladinen [302]
2 years ago
15

MARKING BRAINLIEST TO FIRST CORRECT ANSWER If quadrilateral JKLM had a translation where all the vertices were in the third quad

rant, what would be the coordinates of the vertices?

Mathematics
1 answer:
Likurg_2 [28]2 years ago
6 0

If quadrilateral JKLM were in third quadrant then the coordinates will be (-1,0),(-4,-1),(-4,-2)(-1,-2)

Given Quadrilateral JKLM is in fourth quadrant and coordinates (1,0),(4,-1),(4,-2)(1,-2)

We know that the coordinates of x used to negative in third quadrant and positive in fourth quadrant. Coordinates of y used to negative in third and fourth quadrant.

So in order to change the coordinates from fourth to third we need to change the coordinates of x axis to negative and the coordinates will be :

Coordinates of J will change from (1,0) to (-1,0)

Coordinates of  K will change from(4,-1) to (-4,-1)

Coordinates of L will change from (4,-2) to (-4,-2)

Coordinates of M will change from (1,-2) to (-1,-2).

Learn more about coordinates at brainly.com/question/17206319

#SPJ10

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Answer:

900.

Step-by-step explanation:

1) the initial area is: A₀=0.5*base*h;

2) the final area is: A=0.5*(5*base)*(5*h).

It means, that 25A₀=A, then A=900 [cm²].

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Step-by-step explanation:

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3 years ago
96 inches=_______feet?
Alex787 [66]
12 inches = 1 foot
96 inches = x feet

12/96 = 1/x

Cross multiply

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4 years ago
(◞ ‸ ◟) PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP ≧﹏≦
Marrrta [24]
<h2>It is an obtuse angle.</h2>

Step-by-step explanation:

Obtuse: An obtuse angle is an angle more than 90^\circ but less than 180^\circ.

Example : 110^\circ,135^\circetc.

Acute : An acute angle is an angle less than 90^\circ

Example : 30^\circ,45^\circ etc.

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Since the angle is more than 90^\circ but less than 180^\circ . So, it is an obtuse angle.

4 0
4 years ago
The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0
4 years ago
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