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Paladinen [302]
1 year ago
15

MARKING BRAINLIEST TO FIRST CORRECT ANSWER If quadrilateral JKLM had a translation where all the vertices were in the third quad

rant, what would be the coordinates of the vertices?

Mathematics
1 answer:
Likurg_2 [28]1 year ago
6 0

If quadrilateral JKLM were in third quadrant then the coordinates will be (-1,0),(-4,-1),(-4,-2)(-1,-2)

Given Quadrilateral JKLM is in fourth quadrant and coordinates (1,0),(4,-1),(4,-2)(1,-2)

We know that the coordinates of x used to negative in third quadrant and positive in fourth quadrant. Coordinates of y used to negative in third and fourth quadrant.

So in order to change the coordinates from fourth to third we need to change the coordinates of x axis to negative and the coordinates will be :

Coordinates of J will change from (1,0) to (-1,0)

Coordinates of  K will change from(4,-1) to (-4,-1)

Coordinates of L will change from (4,-2) to (-4,-2)

Coordinates of M will change from (1,-2) to (-1,-2).

Learn more about coordinates at brainly.com/question/17206319

#SPJ10

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¿Cual es el error maximo que se puede cometer al medir el diametro de un circulo, cuya medida es 10 cm y la tolerancia debe ser
ZanzabumX [31]

Usando proporciones, hay que el error maximo que se puede cometer al medir el diametro de un circulo, en cm, es de \pm 0.5.

<h3>¿Qué es una proporción?</h3>

Una proporción es una fracción de la cantidad total.

En este problema:

  • La cantidad total es el diametro de un circulo, cuya medida es 10 cm.
  • El erro maximo es de 5% de esto, o sea:

\pm 0.05(10) = 0.5

El error maximo que se puede cometer al medir el diametro de un circulo, en cm, es de \pm 0.5.

Puede-se aprender más a cerca de proporciones en brainly.com/question/26395519

3 0
2 years ago
Is this answer right?
Klio2033 [76]

Answer:

yes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
When a baseball is hit by a batter the height of the ball age of T at time TT equals zero is determined by the equation age of T
Luda [366]

Answer:

1 ≥ t ≤ 3

Step-by-step explanation:

Given

h(t) = -16t² + 64t + 4

Required

Determine the interval which the bar is at a height greater than or equal to 52ft

This implies that

h(t) ≥ 52

Substitute -16t² + 64t + 4 for h(t)

-16t² + 64t + 4 ≥ 52

Collect like terms

-16t² + 64t + 4 - 52 ≥ 0

-16t² + 64t - 48 ≥ 0

Divide through by 16

-t² + 4t - 3 ≥ 0

Multiply through by -1

t² - 4t + 3 ≤ 0

t² - 3t - t + 3 ≤ 0

t(t - 3) -1(t - 3) ≤ 0

(t - 1)(t - 3) ≤ 0

t - 1 ≤ 0 or t - 3 ≤ 0

t ≤ 1 or t ≤ 3

Rewrite as:

1 ≥ t or t ≤ 3

Combine inequality

1 ≥ t ≤ 3

5 0
2 years ago
Hello, happy Friday, I am just here with some geometry questions.
Hatshy [7]

Answer:

B

Step-by-step explanation:

So far, we know that:

∠D = ∠J.

And that:

DE:JK = 14:7 = 2:1

So, to prove that ΔDEF ~ ΔJKL by SAS, DF must be similar to JL, as those are the sides between the angle.  

So:

DF:JL = 2:1.

Our answer is B.

4 0
2 years ago
Help plz it is only one question
Akimi4 [234]
It would be 43.75% because 

7÷16=0.4375
0.4375×100=43.75%
3 0
3 years ago
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