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Olegator [25]
3 years ago
13

Put 3/8, 2/5, and 0.38 from least to greatest

Mathematics
2 answers:
Vesnalui [34]3 years ago
5 0
3/8=0.375
2/5=0.4
0.38=0.38

0.375<0.38<0.4

therefore: 3/8,0.38,2/5

*Remember that you can convert fractions to decimals by dividing the numerator by the denominator! This makes it much easier to compare :)
Mashcka [7]3 years ago
5 0
2-5, 3-8, and 0.38 and that is how you put it to least to greatest and if it was greatest to least it would be 0.38, 3-8, and 2-5
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The linear equation y = mx + b contains the point (4, -2) and is perpendicular to the
xenn [34]

A linear equation is represented as: y = mx + b.

The equation of the line is: y =3x - 14

First, we calculate the slope (m) of 6x + 18y = 11

Make y the subject

18y = -6x + 11

Divide by 18

y = -\frac{1}{3}x + \frac{11}{18}

In y = mx + b

m \to slope

So, the slope of y = -\frac{1}{3}x + \frac{11}{18} is:

m = -\frac 13

Since, the line is perpendicular to 6x + 18y = 11

The slope of the line is:

m_1 = -\frac{1}{m}

So, we have:

m_1 = -\frac{1}{-1/3}

m_1 = 3

The line passes through (4,-2).

So, the equation is:

y =m(x - x_1) + y_1

This gives:

y =3(x - 4) -2

y =3x - 12 -2

y =3x - 14

Hence, the linear equation is:

y =3x - 14

Read more about  at:

brainly.com/question/11897796

7 0
3 years ago
41 - 17= <br> i know it's 28 but i can't really do math
VikaD [51]
It’s 24 you can use a calculator
4 0
2 years ago
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Nine out of ten students prefer math class over lunch. How many students do not prefer math if 200 students were asked?
fredd [130]
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3 years ago
Solve this question
aleksklad [387]
The answer will be C 
6 0
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Simplify the function. Than determine the key aspects of the function
Tom [10]

To simplify the function, we need to know some basic identities involving exponents.


1. b^(ax)=(b^x)^a=(b^a)^x

2. b^(x/d) = (b^x)^(1/d) = ((b^(1/d)^x)


Now simplify f(x), where

f(x)=(1/3)*(81)^(3*x/4)

=(1/3)(3^4)^(3*x/4) [ 81=3^4 ]

=(1/3)(3^(4*3*x/4) [ rule 1 above ]

=(1/3) (3^(3*x)

=(1/3)(3^(3x)) [ or (1/3)(27^x), by rule 1 ]



(A) Initial value is the value of the function when x=0, i.e.

initial value

= f(0)

=(1/3)(3^(3x))

=(1/3)(3^(3*0))

=(1/3)(3^0)

=(1/3)(1)

=1/3


(B) the simplified base base is 3 (or 27 if the other form is used)


(C) The domain for an exponential function is all real values ( - &infin; , + &infin; ).


(D) The range of an exponential function with a positive coefficient and without vertical shift is ( 0, + &infin; ).

8 0
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