Question

Assuming the amount of money college students spend on text books each semester is symmetrical with a mean of 500 and a standard deviation of 50. Jane paid $550 for her books and wants to know what percentage of students paid MORE than she did for textbooks. So, what percentage of students paid MORE than Jane

Answer 1

16% percent of the students paid MORE than Jane.

The mean(μ) of money spent on textbooks is 500

The standard deviation(σ) of money spent on textbooks is 50

Money paid by Jane for her books is $550

We will use this formula,

Ζ=x-μ/σ

To find: the percentage of students paid MORE than Jane for the textbooks

$P(X > 550)$=?

Solution:

$P(X > 550)=1-P(X$≤$550)$

=$1-P($Ζ≤$\frac{550-500}{50} )$

=1-P(Ζ≤ 1)

=1-0.8413

=0.1587

≈16%

Therefore, 16% percent (approx) of the students paid MORE than Jane.

Learn more about mean and standard deviation here brainly.com/question/4388715

#SPJ4