Answer: ![\bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}](https://tex.z-dn.net/?f=%5Cbold%7BD.%5C%20%5Cdfrac%7Bx%2B4%7D%7Bx%7D%5C%20where%5C%20x%20%5Cneq%200%2C%20%5Cdfrac%7B2%7D%7B3%7D%7D)
<u>Step-by-step explanation:</u>
f(x) = 3x² + 10x - 8
g(x) = 3x² - 2x
![\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}](https://tex.z-dn.net/?f=%5Cdfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%3D%5Cdfrac%7B3x%5E2%2B10x-8%7D%7B3x%5E2-2x%7D%3D%5Cdfrac%7B%283x-2%29%28x%2B4%29%7D%7Bx%283x-2%29%7D%3D%5Cdfrac%7Bx%2B4%7D%7Bx%7D)
Restriction on x: the denominator cannot be equal to zero. So,
x(3x - 2) ≠ 0
→ x ≠ 0 and 3x - 2 ≠ 0
3x ≠ 2
x ![\neq \dfrac{2}{3}](https://tex.z-dn.net/?f=%5Cneq%20%5Cdfrac%7B2%7D%7B3%7D)
Answer:
If the outside diameter of the wheel is 66cm, it will travel 1 wheel circumference. Circumference is Pi x diameter = 3.14 x 66 = 207.24 cm.Step-by-step
Explanation:
If the diameter is of the wheel (without the tire) you need to calculate the actual diameter from the outermost edge of the tire.
Answer:
![r^{6}](https://tex.z-dn.net/?f=r%5E%7B6%7D)
Step-by-step explanation:
To make this a bit easier to see, we'll expand that expression.
R to the 9th is just r times itself 9 times. R to the third is r times itself 3 times.
(excuse my bad formatting)
<u>The expression:</u>
<u>r • r • r • r • r • r • r • r • r • 1</u>
r • r • r • 1
Remember, anything and everything has a coefficient or denominator of 1.
So, we can cancel 3 r's from the numerator and denominator.
<u>r • r • r • r • r • r • 1</u>
1
Simplify....
![\frac{1r^{6}}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B1r%5E%7B6%7D%7D%7B1%7D)
That just equals
.
Answer:
x² - 5x = 14
x = -2 or x = 7
Step-by-step explanation:
x² - 5x = 14
x² - 5x - 14 = 0
(x+2)(x-7) = 0
x = -2 or x = 7