Answer:
option D
Explanation:
given,
mass of the rifle,M = 2 Kg
mass of the bullet , m = 0.01 Kg
speed of the bullet, v = 200 m/s
recoil velocity ,v'= ?
initial velocity of bullet and rifle is zero.
using conservation of energy
Mu + m u' = M v'+ m v
0 + 0 = 2 x v' + 0.01 x 200
2 v' = -2
v' = -1 m/s
negative sign represent the velocity of rifle is in opposite direction of bullet.
hence, the correct answer is option D
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Answer:
B) 
Explanation:
The electric force between charges can be determined by;
F = 
Where: F is the force, k is the Coulomb's constant,
is the value of the first charge,
is the value of the second charge, r is the distance between the centers of the charges.
Let the original charge be represented by q, so that;
= 2q
= 
So that,
F = 
x 
= 2q x
x 
=
x 
=
x 
F =
x 
The electric force between the given charges would change by
.