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SSSSS [86.1K]
3 years ago
7

What is the difference between p-n junction diode and extrinsic semiconductor?

Physics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

The difference between P-N junction diode and extrinsic semiconductor is the allowable direction of flow of current

The extrinsic semiconductor can allow current to flow in both directions while the P-N junction diode permits only a unidirectional flow of current

Explanation:

A semiconductor is a substance that has an intermediate conductivity between that of conductors and non conductors

Examples of semiconductors  include germanium and cadmium selenide

A semiconductor to which impurities has been added (an activity known as doping) is an extrinsic semiconductor

Based on the functioning of a semiconductor, doping result in the formation of one of two types of semiconductors including;

1) N-type semiconductor that has an extra electron and the charge carriers are electrons

2) P-type semiconductor that has one less (-e⁻) electron and holes are the charge carriers

An extrinsic semiconductor can conduct allow the flow of electricity in both ways

A P-N junction diode consists of both the P and N-type extrinsic semiconductors arranged such that current can flow in only one direction.

Therefore, the difference is that the extrinsic semiconductor can allow current flow in both directions while the P-N junction diode permits only a unidirectional flow of current.

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Answer:

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5 0
3 years ago
A truck with a mass of 1370 kg and moving with a speed of 12.0 m/s rear-ends a 593 kg car stopped at an intersection. The collis
Elza [17]

Answer:

speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

Explanation:

Given:

mass of truck M = 1370 kg

speed of truck = 12.0 m/s

mass of car m = 593 kg

collision is elastic therefore,

Applying law of momentum conservation we have

momentum before collision = momentum after collision

1370×12 + 0( initially car is at rest) = 1370×v1+ 593×v2               ....(i)

Also for a collision to be elastic,

velocity of approach = velocity of separation

12 -0 = v2-v1                  ....(ii)

using (i) and (ii) we have

So speed of car after collision, v2 =16.1 m/s and of the truck, v1 = 4.6 m/s

4 0
3 years ago
What type of motion occurs when an object spins around an axis without altering its linear position?
dimulka [17.4K]
That would be only rotational motion
5 0
3 years ago
Two equal point charges QQQ are separated by a distance ddd. One of the charges is released and moves away from the other due on
lys-0071 [83]

Answer:

The kinetic energy K of the moving charge is K = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd

Explanation:

The potential energy due to two charges q₁ and q₂ at a distance d from each other is given by U = kq₁q₂/r.

Now, for the two charges q₁ = q₂ = Q separated by a distance d, the initial potential energy is U₁ = kQ²/d. The initial kinetic energy of the system K₁ = 0 since there is no motion of the charges initially. When the moving charge is at a distance of r = 3d, the potential energy of the system is U₂ = kQ²/3d and the kinetic energy is K₂.

From the law of conservation of energy, U₁ + K₁ = U₂ + K₂

So, kQ²/d + 0 = kQ²/3d + K

K₂ = kQ²/d - kQ²/3d = 2kQ²/3d

So, the kinetic energy K₂ of the moving charge is K₂ = 2kQ²/3d = 2Q²/(4πε)3d = Q²/6πεd

4 0
3 years ago
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Hope this helps!

5 0
2 years ago
Read 2 more answers
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