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SSSSS [86.1K]
3 years ago
7

What is the difference between p-n junction diode and extrinsic semiconductor?

Physics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

The difference between P-N junction diode and extrinsic semiconductor is the allowable direction of flow of current

The extrinsic semiconductor can allow current to flow in both directions while the P-N junction diode permits only a unidirectional flow of current

Explanation:

A semiconductor is a substance that has an intermediate conductivity between that of conductors and non conductors

Examples of semiconductors  include germanium and cadmium selenide

A semiconductor to which impurities has been added (an activity known as doping) is an extrinsic semiconductor

Based on the functioning of a semiconductor, doping result in the formation of one of two types of semiconductors including;

1) N-type semiconductor that has an extra electron and the charge carriers are electrons

2) P-type semiconductor that has one less (-e⁻) electron and holes are the charge carriers

An extrinsic semiconductor can conduct allow the flow of electricity in both ways

A P-N junction diode consists of both the P and N-type extrinsic semiconductors arranged such that current can flow in only one direction.

Therefore, the difference is that the extrinsic semiconductor can allow current flow in both directions while the P-N junction diode permits only a unidirectional flow of current.

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You drive 6.00 km at 50.0 km/h and then another 6.00kmat 900 km/h Your average speed over
Cerrena [4.2K]

Explanation:

average speed = total distance travelled / total time travelled

time to travel the first 6km: 6 / 50 = 3/25 (h)

time to travel the next 6km: 6 / 90 = 1/15 (h)

[I think there's problem in the question 'cause 900km/h sounds impossible for normal person to travel in normal condition]

The total time: 3/25 + 1/15 = 14/75 (h)

Average speed over the 12 km drive will be:

\frac{12}{ \frac{14}{75} }  =  \frac{450}{7}  = 64.3 \: km{h}^{ - 1}

8 0
3 years ago
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the
Vesna [10]

Answer:

The height of the cliff from which the ball was dropped from is 224.4m.

\overline{v}={\frac{\Delta x}{\Delta t}}

Given the data in the question;

Initial velocity of the ball;

Time taken by the ball to reach the ground;

Distance or Height of the cliff from which the ball was thrown from;

To get the height of the Cliff, we use the Second Equation of Motion:

Where s is the distance or height,  is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;

Hence, the equation becomes

We substitute the given values into the equation

Therefore, the height of the cliff from which the ball was dropped from is 224.4m

Explanation:

3 0
2 years ago
Read 2 more answers
I really need Brainliest i am desprate
kondor19780726 [428]

Hy tikki! I've asked some questions, so of you find the questions as easy, then answer it. I'll surely mark you as brainliest :)

6 0
3 years ago
A 3.00 kg mass is traveling at an initial speed of 25.0 m/s. What is the
Nitella [24]

Answer:

The magnitude of the force required to bring the mass to rest is 15 N.

Explanation:

Given;

mass, m = 3 .00 kg

initial speed of the mass, u = 25 m/s

distance traveled by the mass, d = 62.5 m

The acceleration of the mass is given as;

v² = u² + 2ad

at the maximum distance of 62.5 m, the final velocity of the mass = 0

0 = u² + 2ad

-2ad = u²

-a = u²/2d

-a = (25)² / (2 x 62.5)

-a = 5

a = -5 m/s²

the magnitude of the acceleration = 5 m/s²

Apply Newton's second law of motion;

F = ma

F = 3 x 5

F = 15 N

Therefore, the magnitude of the force required to bring the mass to rest is 15 N.

4 0
3 years ago
A deuteron consists of one proton and one neutron. A deuteron moving horizontally enters a uniform, vertical magnetic field of 0
Helen [10]

Answer:

Explanation:

Let the velocity of deuteron be v then force on it in magnetic field

Bqv , B is magnetic field and q is charge on deuteron . This force will provide centripetal force for circular path so

mv² / r = Bqv   m is mass of deuteron and r is radius of circular path

v = Bqr / m

(.5 x 1.6 x 10⁻¹⁹ x 55.6 x 10⁻² )/ 3.34 x 10⁻²⁷

= 13.31 x 10⁶ m /s

6 0
2 years ago
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