Answer:
The mass of the block m is:
Explanation:
Let's analyze the block by parts
For the block M
(1)
Where:
For the block m
(2)
Now, let's combines equation (1) and (2):
Finally, let's solve it for block m.
I hope it helps you!
Answer:
Explanation:
Given
When mass is attached to the spring its frequency is
when another mass is attached to
, frequency changes to
frequency of spring mass system is given by
for
for and
divide 1 and 2
squaring
The final velocity of the truck is found as 146.969 m/s.
Explanation:
As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.
Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.
Then, the final velocity will be
Thus, the final velocity of the truck is found as 146.969 m/s.