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Tresset [83]
8 months ago
5

Joey is riding in an elevator which is accelerating upwards at 2.0 m/s2. The elevator weighs 300.0 kg, and Joey weighs 60.0 kg.

What is the tension in the cable that pulls the elevator upwards?
A) 4200 N
B) 9800 N
C) 3700 N
D) 5200 N
Physics
1 answer:
umka2103 [35]8 months ago
6 0

The tension in the cable that pulls the elevator upwards with an acceleration of 2.0 m/s² is 4200 N. The right option is A) 4200 N.

<h3 /><h3>What is tension?</h3>

Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.

To calculate the tension in the cable, we use the formula below.

Formula:

  • T = mg+ma............ Equation 1

Where:

  • T = Tension in the cable
  • m = Mass of the Joey and the elevator
  • a = Acceleration
  • g = Acceleration due to gravity

From the question,

Given:

  • m = (300+60) = 360 kg
  • a = 2 m/s²
  • g = 9.8 m/s²

Substitute these values into equation 2

  • T = (360×9.8)+(360×2)
  • T = 3528+720
  • T = 4248 N
  • T ≈ 4200 to the nearest hundred.

Hence,  the tension in the rope is 4200 N, the right option is A) 4200 N.

Learn more about tension here: brainly.com/question/24994188

#SPJ1

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<u>LC Circuit</u>

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From eq 2:

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sin^2x+cos^2x=1

\displaystyle \left ( \frac{q_1}{q_0} \right )^2+\left ( \frac{i_1}{\omega q_0} \right )^2=1

Operating

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Now we know the value of q_0, we repeat the procedure of eq 1 and eq 2, but now at the second time t_2, and solve for i_2

\displaystyle \omega^2q_2^2+i_2^2=\omega^2q_o^2

Solving for i_2

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