Only when <em>b</em> = 0 or <em>k</em> = 1<em>.</em>
If <em>f(x)</em> = <em>mx</em> + <em>b</em>, then
<em>f</em> (<em>kx</em>) = <em>m</em> (<em>kx</em>) + <em>b</em> = <em>mkx</em> + <em>b</em>
while
<em>k</em> <em>f(x)</em> = <em>k</em> (<em>mx</em> + <em>b</em>) = <em>kmx</em> + <em>kb</em>
The two expression are identical only if
<em>kb</em> = <em>b</em> ===> <em>kb</em> - <em>b</em> = 0 ===> <em>b</em> (<em>k</em> - 1) = 0 ===> <em>b</em> = 0 or <em>k</em> = 1
Answer:
is this for real??
Step-by-step explanation:
no wayy!!
Answer:
I believe it is 2(x-5)²−1
Step-by-step explanation:
The parentheses represent the horizontal shift. (X-__) is a shift to the right. (X+__) is a shift to the left. The last number of the function is the vertical shift. A negative number is shifting down and a post number is shifting up.
So, if the graph shifts up three units, then you add 3 + -4 to get -1. And if the graph shifts right 2 units, then you subtract 2 from -3 to get -5.
