All categories

3 years ago

Which line passes through the origin?

Mathematics

1 answer:

Oksana_A [137]3 years ago

7 0

Answer:

c. y=-3x

Step-by-step explanation:

Plug in x=0 and y=0.

0=-3(0)

0=0...the origin

You might be interested in

Graph the solution to this inequality on the number line.

gladu [14]

Answer: x>8
Subtract 8 from both sides -6x< -48 (40 is a negative so -8 will just add to it)
Divide -48 and -6
X< 8 (since they’re both negative it’ll turn into a positive because we divided)
Turn the <
X>8

8 0

4 years ago

Find the absolute value of the complex number 5 - 4i.

Damm [24]

I answered a similar question for someone else. The absolute value of a complex number is called the modulus. This represents the DISTANCE to the origin from the point on the imaginary + real plane.
the real horizontal distance is 5 and the imaginary vertical distance is in this case 4 (from -4i) the distance is 4. So to figure out this just use the Pythagorean theorem.
5^2 + (4)^2 = c^2
25 +16 = c^2
c^2 = 41c = 6.4 So option D.

8 0

3 years ago

Read 2 more answers

You roll 4 fair, distinguishable, six-sided dice. What is the probability of rolling :______

Vikentia [17]

Answer:

a)0.25

b)0.375

Step-by-step explanation:

Possible outcomes when dice are rolled : 1 ,2 ,3,4,5 ,6

Even= 2,4,6

Odd = 1 ,3 , 5

Probability of getting even = $\frac{3}{6}=\frac{1}{2}$

Probability of getting odd = $\frac{3}{6}=\frac{1}{2}$

4 dices are rolled together

a)P(3 even and 1 odd numbers)

P(3 even and 1 odd numbers)= $^4C_3 (\frac{1}{2})^3 (\frac{1}{2})^1$

P(3 even and 1 odd numbers)= $\frac{4!}{3!1!} (\frac{1}{2})^3 (\frac{1}{2})^1 =0.25$

b)P(2 even and 2 odd numbers)

P(2 even and 2 odd numbers)= $^4C_2 (\frac{1}{2})^2 (\frac{1}{2})^2$

P(3 even and 1 odd numbers)= $\frac{4!}{2!2!} (\frac{1}{2})^2 (\frac{1}{2})^2$ =0.375

6 0

3 years ago

Find the volume of the square pyramid and round to the

Brrunno [24]

The answer is to multiply

3 0

3 years ago

Solve: 3(2x - 5) = 6x - 15

Levart [38]

$3(2x-5)=6x-15$

$3(2x-5) :$

$6x-15 = 6x-15$

add 15 to both sides:

$6x-15+15=6x-15+15$

$6x =6x$

subtract 6x from both sides:

$6x-6x=6x-6x$

$0=0$

Both sides are equal : true for all x

Answer D

hope this helps!

3 0

3 years ago