Answer:
a) the COP of this air conditioner is 2.38
b) the rate of heat transfer to the outside air is 1065 kJ/min
Explanation:
Given the data in the question;
[ Outdoor ] ← Q [ W ] Q ← [ House ]
Rate of heat removed from the house; Q = 750 kJ/min = ( 750 kJ/min × ( 1 kW / 60 kJ/min ) ) = 12.5 kW
Net-work input; W = 5.25 kW
a) The coefficient of performance of the air conditioner; COP.
COP = Q / W
we substitute
COP = 12.5 kW / 5.25 kW
COP = 2.38
Therefore, the COP of this air conditioner is 2.38
b) the rate of heat transfer to the outside air.
Q = Q + W
we substitute
Q = 12.5 kW + 5.25 kW
Q = 17.75 kW
Q = ( 17.75 × 60 ) kJ/min
Q = 1065 kJ/min
Therefore, the rate of heat transfer to the outside air is 1065 kJ/min
Answer: 5.36×10-3kg/h
Where 10-3 is 10 exponential 3 or 10 raised to the power of -3.
Explanation:using the formula
M =JAt = -DAt×Dc/Dx
Where D is change in the respective variables. Insulting the values we get,
=5.1 × 10-8 × 0.13 × 3600 × 2.9 × 0.31 / 4×10-3.
=5.36×10-3kg/h
Answer:
time need = 17.65 minutes
Explanation:
given data
water flows in = 22 liters/minute
water flows out = 5 liters/minute
volume of water needed for a bath = 0.30 m³ = 300 Liters
Density of water = 1000 kg/m³
solution
we get here time for need to fill bath that is express as
time need = .........................1
put here value and we will get
time need =
time need = 17.65 minutes
HEY GIRLLL IM BACK LOL. 4x + 2y = 20 ?
Answer:
Factors to be considered when changing or enhancing a design are:
1)The overall aesthetic
2)plausibility
3)cost, and
4 )Efficiency of the new final product.
All these are all important factors to consider.