Answer:
Explanation:
Given that
L= 50 m
Pressure drop = 130 KPa
For Copper tube is 3/4 standard type K drawn tube
Outside diameter=22.22 mm
Inside diameter=18.92 mm
Dynamic viscosity for kerosene
Pressure difference given as
Where
L is length of tube
μ is dynamic viscosity
Q is volume flow rate
d is inner diameter of tube
ΔP is pressure drop
Now by putting the values
So flow rate is
Answer: 35.3 °
Explanation:
Body-centered cubic lattice (bcc or cubic-I), just like all lattices, has lattice points at the eight corners of the unit cell with an additional points at the center of the cell. It has unit cell vectors a = b = c and interaxial angles α=β=γ=90°.
The simplest crystal structures are those that have present only a single atom at each lattice point.
body-centered cubic unit cell has atoms at each of the eight corners of a cube (like the cubic unit cell) plus one atom in the center of the cube. Each of the corner atoms is the corner of another cube so the corner atoms are shared between eight unit cells. It is said to have a coordination number of 8. The bcc unit cell consists of a net total of two atoms; one in the center and eight eighths from corners atoms
With the use of BCC unit cell, if a applied stress is in [110] direction, but slip applies in [111] direction, the angle between applied direction and slip direction is given as:
[1 1 0] [1 1 1]
λ = Cos^-1 ( 1×1 + 1×1 + 0×1 ÷ (1^2 + 1^2 +0^2) (1^2 + 1^2+ 1^2))
Cos^-1 2/ sqrt 6
= 35.386°
Hazard is a possible source of danger
Answer:
Tension in wire will be
Explanation:
We have given seed of the transverse wave v = 400 m/sec
Linear density = 0.10 g/cm
We know that 1 gram = 0.001 kg
And 1 cm = 0.01 m
So
We know that speed of wave is given by , here T is tension in the wire
So
Squaring both side
T =
So tension in wire will be