A compound was decomposed and determined to be 51.27 % C, 7.75 % H and 40.98 % O by mass. What is the subscript for H in the emp
1 answer:
The subscript for H in the empirical formula for this compound is 3.
There are 3 steps involved in the construction of empirical formula.
Calculation of empirical formula is as under as ...
Step 1: Divide the % of each atoms which their atomic weights.
C = 51.27 / 12 = 4.27
H = 7.75 / 1 = 7.75
O = 40.98 / 16 =2.56
Step 2 : Divide all the answers with the smallest answer to get the subscripts for empirical formula.
C = 4.27/ 2.56 ≈ 2
H = 7.75/ 2.56 ≈ 3
O = 2.56 /2.56 = 1
Step 3: Construction of empirical formula by putting subscripts calculated in step 2.
Empirical formula form given data =
Thus , subscript for H in the empirical formula for this compound is 3.
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Answer:
1) The new pressure of the gas is 500 kilopascals.
2) The final volume is 1.44 liters.
3) Volume will decrease by approximately 67 %.
4) The Boyle's Laws deals with pressures and volumes.
Explanation:
1) From the Equation of State for Ideal Gases we construct the following relationship:
(1)
Where:
- Initial and final pressure, measured in kPa.
- Initial and final pressure, measured in mililiters.
If we know that ,
and
, then the new pressure of the gas is:
The new pressure of the gas is 500 kilopascals.
2) Let suppose that gas experiments an isothermal process. From the Equation of State for Ideal Gases we construct the following relationship:
(1)
Where:
- Initial and final pressure, measured in kPa.
- Initial and final pressure, measured in mililiters.
If we know that ,
and
then the new volume of the gas is:
The final volume is 1.44 liters.
3) From the Equation of State for Ideal Gases we construct the following relationship:
(1)
Where:
- Initial and final pressure, measured in kPa.
- Initial and final pressure, measured in mililiters.
If we know that , then the volume ratio is:
Volume will decrease by approximately 67 %.
4) The Boyle's Laws deals with pressures and volumes.