A compound was decomposed and determined to be 51.27 % C, 7.75 % H and 40.98 % O by mass. What is the subscript for H in the emp
1 answer:
The subscript for H in the empirical formula for this compound is 3.
There are 3 steps involved in the construction of empirical formula.
Calculation of empirical formula is as under as ...
Step 1: Divide the % of each atoms which their atomic weights.
C = 51.27 / 12 = 4.27
H = 7.75 / 1 = 7.75
O = 40.98 / 16 =2.56
Step 2 : Divide all the answers with the smallest answer to get the subscripts for empirical formula.
C = 4.27/ 2.56 ≈ 2
H = 7.75/ 2.56 ≈ 3
O = 2.56 /2.56 = 1
Step 3: Construction of empirical formula by putting subscripts calculated in step 2.
Empirical formula form given data =
Thus , subscript for H in the empirical formula for this compound is 3.
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Answer:
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Explanation:
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Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)
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<u>Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants) = (2+1)-(2+2) = -1 </u>
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