Answer:
The partial pressure of CO₂ will decrease.
Explanation:
The reaction:
2CO (g) + O₂ (g) ⇄ 2CO₂ (g) has a ΔH = –566 kJ/mol. As ΔH<0, the reaction is exothermic.
Le Chatelier's principle says that if a system in chemical equilibrium is subjected to a disturbance it tends to change in a way that opposes this disturbance.
In this case, with increasing of the temperature, the system will produce less heat, doing the equilibrium shifts to the left.
Thus, the partial pressure of both CO and O₂ will increase. And<em> partial pressure of CO₂ will decrease.</em>
I hope it helps!
Oxygen gas produced : 0.7 g
<h3>Further explanation</h3>
Given
10.0 grams HgO
9.3 grams Hg
Required
Oxygen gas produced
Solution
Reaction⇒Decomposition
2HgO(s)⇒2Hg(l)+O₂(g)
Conservation of mass applies to a closed system, where the masses before and after the reaction are the same
mass of reactants = mass of products
mass HgO = mass Hg + mass O₂
10 g = 9.3 g + mass O₂
mass O₂ = 0.7 g
Atoms. Well, they can be broken down, but that won't happen that fast.
Answer the glucose is then turned back into carbon dioxide, which is used in photosynthesis
Explanation: :)
