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1 year ago

A lone pair must reside in which orbital type(s) to participate in resonance/conjugation/delocalization?

1 answer:

5 0

If a lone pair is participating in resonance, this capability the atom is both Sp2 or Sp hybridized. Looking at the Sp2 case, that ability there are 3 Sp2 orbitals and one P orbital. Assuming there is no formal cost on the atom, the three hybrid orbitals are used for bonding and the lone P-orbital holds the lone pair. Sp3 orbitals are no longer involved with resonance so the lone pair worried in resonance should never be in an Sp3 orbital.

A mathematically described area round a nucleus in an atom or molecule that may also include zero, one, or two electrons Electrons organize themselves in cloudlike areas round the nucleus referred to as orbitals.

Learn more about orbitals here:

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Draw the lewis structure for so42-. How many equivalent resonance structures can be drawn?

Elena-2011 [213]

Answer : The Lewis-dot structure and resonating structure of $SO_4^{2-}$ is shown below.

Explanation :

Resonance structure : Resonance structure is an alternating method or way of drawing a Lewis-dot structure for a compound.

Resonance structure is defined as any of two or more possible structures of the compound. These structures have the identical geometry but have different arrangements of the paired electrons. Thus, we can say that the resonating structure are just the way of representing the same molecule.

First we have to determine the Lewis-dot structure of $SO_4^{2-}$ .

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $SO_4^{2-}$

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $SO_4^{2-}$ = 6 + 4(6) + 2 = 32

According to Lewis-dot structure, there are 12 number of bonding electrons and 20 number of non-bonding electrons.

Hence, the Lewis-dot structure and resonating structure of $SO_4^{2-}$ is shown below.

8 0

3 years ago

Help me please help...

Mashcka [7]

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases. -google

its probably 40

8 0

2 years ago

How to put Roman numerals in a science equation

Bogdan [553]

Example:

Oxygen(III)

6 0

3 years ago

Will mark the brainiest later for correct answers! Please show work.

Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number $6.023\times 10^{23}$ of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}$

a. moles in 14.08 g of $C_{12}H_{22}O_{11}$ = $\frac{14.08g}{342.3g/mol}=0.04113moles$

molecules in 14.08 g of $C_{12}H_{22}O_{11}$ = $0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}$

b. moles in 17.75 g of NaCl = $\frac{17.75g}{58.5g/mol}=0.3034moles$

molecules in 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

formula units 17.75 g of $NaCl$ = $0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}$

c. moles in 20.06 g of $CuSO_4.5H_2O$ = $\frac{20.06g}{249.68g/mol}=0.08034moles$

formula units in 20.06 g of $CuSO_4.5H_2O$ = $0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}$

7 0

2 years ago

Science plz help due soon 6th grade Major grade

pentagon [3]

Answer:

the answer is d.

Explanation:

because the core is deepest then is the mantle and the lithpsphere is last .

I put a picture incase you need a visual example.

5 0

2 years ago