Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.
1 answer:
Answer: The molality of solution is 17.6 mole/kg
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
where,
n = moles of solute
= weight of solvent in kg
moles of acetone (solute) = 0.241
moles of water (solvent )= (1-0.241) = 0.759
mass of water (solvent )=
Now put all the given values in the formula of molality, we get
Therefore, the molality of solution is 17.6 mole/kg
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The reaction is spontaneous at high temperatures, and non-spontaneous at low temperatures.
In a thermodynamically closed system, the measure of the non-expansion work by the system and the enthalpy and the entropy is said to be the <u>Gibbs free energy</u>.
<h3>How to determine the Gibbs free energy?</h3>According to the reaction, the enthalpy change and the change in the entropy
is positive. The Gibbs free energy is given by,
and the reaction will be spontaneous only when the
is negative.
If there is not much effect on the enthalpy and entropy due to a decrease in temperature, then the value of the Gibbs free energy will be positive and will be close to that of the enthalpy change. In the above reaction enthalpy, change is positive and hence the reaction will be non-spontaneous.
When the temperature is increased then the entropy will affect the overall reaction as the Gibbs free energy will have the opposite sign as that of the entropy. So the reaction will become spontaneous at high temperatures.
Thus, option A is correct.
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