1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lisabon 2012 [21]
2 years ago
11

Will a real gas ever reach absolute zero? Will an ideal gas ever reach absolute zero? Why or why not? Compose a report that answ

ers these two questions. 125 words.
Chemistry
1 answer:
Zolol [24]2 years ago
5 0

It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high.

<h3>What is the absolute zero?</h3>

The absolute zero is the temperature at which the movement of all the gas molecules is theoretically believed to cease. At the absolute zero, gas molecules remain at fixed positions because according to the third law of thermodynamics, the entropy of a perfectly ordered system is zero.

It is impossible to reach absolute zero because the magnitude of work that is required to remove energy from a gas in order to attain the absolute zero is so high such that it is impractical to attain the absolute zero.

Learn more about absolute zero:brainly.com/question/79835

#SPJ1

You might be interested in
How long does Neptune take to rotate on its axis?
Ray Of Light [21]
23.934 Hours Is how long it tales.
8 0
3 years ago
Which of the following reasons best explains why water isn
Sholpan [36]

Answer:

the wax is a nonpolar substance that will not mix with polar water

Explanation:

Water is polar by due to the uneven distribution of charge between the hydrogen and oxygen. T=This automatically eliminates options 3 and 4.

Wax on the other hand is a non polar substance. Due to this non polar characteristic, it would not dissolve in water. The correct option is;

- the wax is a nonpolar substance that will not mix with polar water

3 0
3 years ago
Calculate how many grams of hydrogen can be burned if 40. liters of oxygen at 200. k and 1.0 atm. show work pls.
Wittaler [7]

The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.

<h3>How do we calculate grams from moles?</h3>

Grams (W) of any substance will be calculated by using their moles (n) through the following equation:

  • n = W/M, where

M = molar mass

And moles of the gas will be calculated by using the ideal gas equation as:

  • PV = nRT, where

P = pressure = 1atm

V = volume = 40L

n = moles = ?

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature = 200K

On putting these values on the above equation, we get

n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles

  • Now grams of hydrogen gas will be calculated by using the first equation as:

W = (2.44mol)(2g/mol) = 4.88g

Hence required mass of hydrogen gas is 4.88g.

To know more about ideal gas equation, visit the below link:

brainly.com/question/15046679

#SPJ1

7 0
3 years ago
To what volume should you dilute 60.0 mL of a 4.50 M KI solution so that 30.0 mL of the diluted solution contains 3.25 g of KI?
SpyIntel [72]

Answer:

You should dilute to 414.1 mL

Explanation:

Let's apply the dilution formula to solve this:

M conc . Vol conc = M dil . Vol dil

Molarity for concentrated solution → 4.50 M

Volume for concentrated solution → 60 mL

Molarity for diluted solution → Unknown

Volume for diluted solution → Answer

Let's determine the molarity for diluted solution with data given.

We convert the mass of KI to moles

3.25 g . 1 mol/166 g = 0.0195 moles

Let's convert the volume from mL to L

30 mL . 1 L/1000mL = 0.030 L

Molarity (mol/L) = 0.0195 mol /0.030L = 0.652 M

We replace the data in the formula

4.50 M . 60 mL = 0.652 M . Volume for diluted solution

(4.50M . 60mL) / 0.652M = Volume for diluted solution

414.1 mL = Volume for diluted solution

7 0
3 years ago
Read 2 more answers
3.0 cm x 4.0 cm x 1.0 cm<br><br>[?]cm^3​
CaHeK987 [17]

Explanation:

<em>Hi</em><em> </em><em>there</em><em>!</em><em>!</em>

<em>you</em><em> </em><em>asked</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>these</em><em> </em><em>all</em><em> </em><em>right</em><em>,</em>

<em>you</em><em> </em><em>can</em><em> </em><em>simply</em><em> </em><em>multiply</em><em> </em><em>it</em><em> </em><em>,</em>

<em>=</em><em>3</em><em>cm</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>cm</em><em> </em><em>×</em><em> </em><em>1</em><em>cm</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>2</em><em>×</em><em>1</em><em>cm</em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>4</em><em>×</em><em>3</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>=</em><em> </em><em>1</em><em>2</em><em>cm</em><em>^</em><em>3</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>1</em><em>2</em><em>×</em><em>1</em><em>=</em><em>1</em><em>2</em><em>)</em>

<em>Therefore</em><em>, </em><em> </em><em>the</em><em>answer is</em><em> </em><em>1</em><em>2</em><em> </em><em>cm</em><em>^</em><em>3</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
4 years ago
Other questions:
  • Which liquid would be the most difficult to raise or lower the temperature of
    13·2 answers
  • A chemical reaction produced 177.3 grams of chlorine has (Cl²). What was the volume of the gas?
    12·1 answer
  • A gas does not have a fixed volume. As a result, a gas also does not have a fixed, constant _______. A. chemical composition B.
    9·2 answers
  • Will mark brainliest!!!!!
    12·2 answers
  • Human blood has a pH between 7.38 and 7.42. What can one conclude about human blood?
    8·1 answer
  • One way to remove lead ion from water is to add a source of iodide ion so that lead iodide will precipitate out of solution: Pb2
    11·1 answer
  • Someone help ,, I'll give brainliest lolll .
    11·1 answer
  • Explain what would happen to the air temperature at Riverdale School over the course of the
    11·1 answer
  • Calculate the chemical amount of ammonia present in a 11.22g sample of the compound​
    12·1 answer
  • Can someone plz help me? :(
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!