1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rainbow [258]
2 years ago
10

{(3,-2), (4,-2),(5,-2), (6,-2)} is this a function

Mathematics
1 answer:
irga5000 [103]2 years ago
4 0

Answer:

{(3,-2), (4,-2),(5,-2), (6,-2)}  this relation is not a function.

You might be interested in
"A curtain manufacturer uses a 9090-yard roll of material to make 77 identical curtains. There was 7.757.75 yards of material le
34kurt

Answer:

Step-by-step explanation:

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=5x%2B7x-1%2F2x%2B1%2F4%3D6%5C%5Cx%3D%3F" id="TexFormula1" title="5x+7x-1/2x+1/4=6\\x=?" alt="5
fredd [130]

Answer:

Step-by-step explanation:

5x + 7x - 1/2x + 1/4 = 6

move x to one side move numbers to the other side

5x + 7x - 1/2 x = 6 - 1/4

add x and numbers

23/2x = 23/4

divide both side by 23/2

x = (23/4)/(23/2)

  = 1/2

plug it in to check the answer

5/2 + 7/2 - 1/4 + 1/4 = 6

12/2 = 6

6 0
2 years ago
A soccer team sold raffle tickets to raise money for the upcoming season. They sold three different types of tickets: premium fo
lesya692 [45]

Answer:

45 premium tickets were sold

Step-by-step explanation:

p = premium

d = deluxe

r = regular

p+d+r = 273

6p+4d + 2r = 836

118+d = r

Replace r with 118+d

p+d+118+d = 273

p +2d = 273-118

p+2d = 155

6p+4d + 2(118+d) = 836

6p+4d + 236+2d = 836

6p +6d = 836-236

6p + 6d = 600

Divide by 6

p+d = 100

d = 100-p

Replace d in p +2d= 155

p +2(100-p) = 155

p+200-2p = 155

-p = 155-200

-p =-45

p =45

45 premium tickets were sold

3 0
3 years ago
Read 2 more answers
does the pythagorean theorem hold for shapes other than squares constructed on the legs and hypotenuse of a right triagles
Fudgin [204]
It is 7 thousand and a bunch of random numbers

8 0
3 years ago
A rose garden can be planted for $4000. The marginal cost of growing a rose is estimated to $0.30,
wariber [46]

Answer:

C(x)=4000+0.3x

R(x)=1.75x

Profit= 1.45x-4000

Step-by-step explanation:

We are given that A rose garden can be planted for $4000.

The marginal cost of growing a rose is estimated to $0.30,

Let x be the number of roses

So, Marginal cost of growing x roses = 0.3x

Total cost = 4000+0.3x

So, Cost function : C(x)=4000+0.3x ---A

Now we are given that the total revenue from selling 500 roses is estimated to $875

So, Marginal revenue = \frac{\text{Total revenue}}{\text{No. of roses}}

Marginal revenue = \frac{875}{500}

Marginal revenue = 1.75

Marginal revenue for x roses  = 1.75x

So, Revenue function =  R(x)=1.75x ----B

Profit = Revenue - Cost

Profit= 1.75x-4000-0.3x

Profit= 1.45x-4000  ---C

Now Plot A , B and C on Graph

C(x)=4000+0.3x  -- Green

R(x)=1.75x  -- Purple

Profit= 1.45x-4000  --- Black

Refer the attached graph

6 0
3 years ago
Other questions:
  • Henry works 140 hours each month and earns 12 per hour. show how to use the distributive law to find how Henry earns each month
    7·2 answers
  • MATH HELP
    11·2 answers
  • Karen owns a seafood restaurant. She orders trout from an online retailer. Each pound of trout costs $32, and the company charge
    7·2 answers
  • to mix a punch, Lindsay begins with 3 liters of lemon lime soda and adds 1,893 millilters of cranberry juice. How many liters ar
    13·2 answers
  • 0.0125 in a fraction in simplest form
    12·2 answers
  • 35 more than 5 times a number, w, is -10, what is the number w?
    10·1 answer
  • A⁵÷a³ help ASAP need for maths HW arrrrrgggghhh
    14·2 answers
  • How can you rewrite 12x+4y=32 in y form
    10·1 answer
  • Please help asap&lt;3(grade 8 question)
    5·1 answer
  • A client is withdrawing $105.83. He would like $40 in $10 bills and the rest in the fewest number of bills and coins possible. S
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!