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3 years ago

10

The graph models the projected populations, in thousands, of two towns after x years. Both towns experience a 1.9% annual growth

rate.

1 answer:

spin [16.1K]3 years ago

3 0

whats the question

?

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$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{2}\right)^{2\cdot 19}\implies A\approx 22194.067 \\\\[-0.35em] ~\dotfill$

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{1}\right)^{1\cdot 19}\implies A\approx 21578.505$

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2 years ago

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