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Elena L [17]
2 years ago
7

The heat of vaporization of water is 540 cal/g. How much heat is needed to change 4.28g of water to steam?

Chemistry
1 answer:
damaskus [11]2 years ago
7 0

Answer:

2311.2 cal

Explanation:

540 cal / g    *   4.28 g = 2311.2  cal

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Read 2 more answers
Butane (C4 H10(g), mc031-1.jpgHf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , mc031-2.jpgHf = –393.5 kJ/
ankoles [38]

The balanced chemical equation for the combustion of butane is:

2C_{4}H_{10}(g) +13 O_{2}(g)-->8CO_{2}(g)+10H_{2}O(g)

ΔH_{reaction}^{0} = Σn_{products}ΔH_{f}^{0}_{(products)}-Σn_{reactants}ΔH_{f}^{0}_{(reactants)}

                         = [{8*(-393.5kJ/mol)}+{10*(-241.82kJ/mol)}]-[{2*(-125.6kJ/mol)}+13*(0 kJ/mol)}]=[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]

                      = -5315 kJ/mol

Calculating the enthalpy of combustion per mole of butane:

1mol C_{4}H_{10}*( \frac{-5315kJ}{2mol C_{4}H_{10} })=-2657.5 \frac{kJ}{molC_{4}H_{10}}

Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol

Correct answer: -2657.5 kJ/mol

6 0
3 years ago
I need help answering numbers 8-10
gizmo_the_mogwai [7]

Answer:

The correct answer:

8)- e)2, 2 dymetilpropane

9)-  b) 2-chloropropane

10)-  b) hydroxyl

See the explanation below, please.

Explanation:

In the cases of exercises 8 and 9:

Correspond to alkanes, having 3 carbons are named with the prefix prop and suffix anus. In 8 it has 2, 2 methyl groups in carbon and 9 in a 2-carbon chlorine group.

In the case of 10, it corresponds to a 3-carbon alcohol: suffix prop, and prefix ol: 2- propanol; in group 2 it has an OH group corresponding to alcohol (hydroxyl).

8 0
3 years ago
What is the product of Na +CaSO4,
OverLord2011 [107]

Answer:

Na + CaSO4 = Na2SO4 + Ca

Explanation:

single displacement (substitution)

8 0
3 years ago
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