Determine the electron-group arrangement, molecular shape, and ideal bond angle(s) for each of the following:
1 answer:
Solution :
a).
This compound is known as sulfur trioxide.
The molecular shape of sulfur trioxide is trigonal planer.
And the bond angle is 120°.
b).
This compound is known as Nitrous oxide. Here, nitrogen is in the center. There is no lone pair around the nitrogen atom and it forms two sigma bonds with the other two atoms.
It is linear in shape.
The bond angle between them is 180°.
c).
This compound is known as the Dichloromethane.
The molecular shape of the compound is tetrahedral.
The bond angles is 120°
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Answer:
<span>Molecular geometry around each carbon atom in a saturated hydrocarbon is Tetrahedral.
Explanation:
</span> In saturated hydrocarbons (-CH₂-) the central atom (carbon) is bonded to either three or two hydrogen atoms and one or two carbon atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to Valence Shell Electron Pair Repulsion (VSEPR) Theory the central atom with four bonding pair electrons and zero lone pair electrons will attain a tetrahedral geometry with bond angles of 109°.
<span>Molecular geometry around each carbon atom in a saturated hydrocarbon is Tetrahedral.
Explanation:
</span> In saturated hydrocarbons (-CH₂-) the central atom (carbon) is bonded to either three or two hydrogen atoms and one or two carbon atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to Valence Shell Electron Pair Repulsion (VSEPR) Theory the central atom with four bonding pair electrons and zero lone pair electrons will attain a tetrahedral geometry with bond angles of 109°.