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2 years ago

I need the answers can u help me please

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

3 0

Answer:

`1) 2.5cm, 2)1.25inches 3)2.25inches 4)1.25inches

Step-by-step explanation:

1) This is a centimeter rule, one small line represents 0.1cm and 1 long line represent 1cm, the line in between two long lines represent 0.5 cm

As you can see from A to B, is 2 cm + 0.5cm = 2.5cm.

2)This is found on the other side of rulers, inches.

1 small line represent 0.25 inches, line in between 2 long lines is 0.5 inches.

From S to T, is 1 inch + 0.25 inches = 1.25inches

3)Similar to Question 2.

Length of Pencil= 2 inches + 0.25 inches = 2.25 inches

4)This is a more detailed inch rule.

But length of heart shape = 1 inch + 0.25 inches = 1.25 inches

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Select two statements that are true about the equation y+4=-8(x-2)

bezimeni [28]

Answer:

Step-by-step explanation:

y + 4 = -8(x - 2)

I dont know the statements that u have but maybe I can guess one...or two

slope = -8

points used were : (2,-4)

y + 4 = -8(x - 2)

y + 4 = -8x + 16

y = -8x + 16 - 4

y = -8x + 12 ............slope intercept form

8x + y = 12 .......standard form

x intercept = (3/2,0)

y intercept = (0,12)

any of that answer ur question ?

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3 years ago

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The answer is B. 60 cubic inches
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3 years ago

8 over 17 subtract fifteen over sixty-eight

astra-53 [7]

8/17-15/68

This will equal 32/68-15/68 if you equalize the denominator. The final answer is 17/68 which equals 1/4 if you reduce.

3 0

3 years ago

Complete the standard form of the equation of a hyperbola that has vertices at (-10, -15) and (70, -15) and one of its foci at (

Elena L [17]

Answer:

$\frac{(x-30)^{2}}{40^{2}} - \frac{(y+15)^{2}}{3^{2}} = 1$

Step-by-step explanation:

The equation of the horizontal hyperbola in standard form is:

$\frac{(x-k)^{2}}{a^{2}} - \frac{(y-k)^{2}}{b^{2}} = 1$

The position of its center is:

$C(x,y) = \left(\frac{-10 + 70}{2}, -15 \right)$

$C(x, y) = (30,-15)$

The values for c and a are respectively:

$a = 70 - 30$

$a = 40$

$c = 30 - (-11)$

$c = 41$

The remaining variable is computed from the following Pythagorean identity:

$c ^{2} = a^{2} + b^{2}$

$b = \sqrt{c^{2}-a^{2}}$

$b = \sqrt{41^{2}-40^{2}}$

$b = 3$

Now, the equation of the hyperbola is:

$\frac{(x-30)^{2}}{40^{2}} - \frac{(y+15)^{2}}{3^{2}} = 1$

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3 years ago

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aleksley [76]

Answer:

You would solve this as if the inequality sign was an equal sign.

Just make sure when you divide by a negative or multiply by a negative the sign switches, anyways:

5 + 5(x +4) < 20

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3 years ago