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ollegr [7]
2 years ago
7

Which of the following is most likely the next step in the series?

Mathematics
1 answer:
ZanzabumX [31]2 years ago
7 0

Answer:

I think the answer is B

Step-by-step explanation:

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What is the volume of the pyramid 6ft?
Rama09 [41]
Can you please clearifie what mean this 6 ft for the pyramid ? this is the length of edge or the length side of base or the height of pyramid - what mean this 6 ft ?
4 0
3 years ago
A water tank is 1/8 full. the tank is 3/4 full when 42 gallons of water are added to the tank. how much water can the tank hold
Rashid [163]

Let, the water capcity of tank = x

it would be x*3/4 = 42

x = 42*4 / 3 = 168/3 = 56

So, the tank can hold up to 56 gallons

3 0
3 years ago
Read 2 more answers
If Pearson’s measure of skewness is 0 the distribution is
solmaris [256]

Answer:

If a distribution isn't skewed, that means it's symmetrical, and potentially normal. Please see the attached picture for a visual representation.

8 0
4 years ago
A website manager has noticed that during the evening​ hours, about 3.23.2 people per minute check out from their shopping cart
aleksandrvk [35]

Answer:

1.  c. Poisson

2. 0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. 0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

Step-by-step explanation:

We have only the mean, which means that the Poisson distribution is used to solve this question, and thus the answer to question 1 is given by option c.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 3.2 minutes:

This means that \mu = 3.2n, in which n is the number of minutes.

2. What is the probability that in any one minute at least one purchase is​ made?

n = 1, so \mu = 3.2.

This probability is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3.2}*3.2^{0}}{(0)!} = 0.0408

So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0408 = 0.9592

0.9592 = 95.92% probability that in any one minute at least one purchase is​ made.

3. What is the probability that no one makes a purchase in the next 2​ minutes?

2 minutes, so n = 2, \mu = 3.2(2) = 6.4

This probability is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-6.4}*6.4^{0}}{(0)!} = 0.0017

0.0017 = 0.17% probability that no one makes a purchase in the next 2​ minutes.

7 0
3 years ago
A=755y/t^2 <br> Solve for y.
timofeeve [1]

Answer:

y = At²/755

Step-by-step explanation:

A = 755y/t²

multiply both sides by t²

At² = 755y

Divide both sides by 755

At²/755 = y

Flip

y = At²/755

5 0
3 years ago
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