Question

(3,3p) and (4,p²+1) has gradient -1 find p​

Answer 1

$\frac{p {}^{2} + 1 - 3p }{4 - 3} = -1$

$p {}^{2} - 3p + 1 = -1$

$p {}^{2} - 3p +2 = 0$

$(p-2)(p - 1) = 0$

$p = 2 \: \: \: \: \: p = 1$