Calculate the mass of water produced by metabolism 84.0 g of glucose
1 answer:
The amount of water that will be produced is 50.36 grams
<h3>Stoichiometric problems</h3>The metabolism of glucose is represented by the following equation:
The mole ratio of glucose metabolized to the water produced is 1:6.
Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles
Equivalent mole of water = 0.4662 x 6 = 2.7975 moles
Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams
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Answer: The salt produced will be
Explanation:
During a neutralization reaction, an acid reacts with a base for producing the correspondent salt, and water.
The strong acids release all the protons avalaible when are dissolved, such as sulfuric acid. As you can see, sulfuric acid have 2 protons ready for being released (); and those places have to be occcupied for other ions equivalents to the H+: K+ from KOH in this case.
Therefore the answer will be .