Calculate the mass of water produced by metabolism 84.0 g of glucose

Chemistry

1 answer:

scoundrel [369]2 years ago

8 0

The amount of water that will be produced is 50.36 grams

<h3>Stoichiometric problems</h3>

The metabolism of glucose is represented by the following equation:

$C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)$

The mole ratio of glucose metabolized to the water produced is 1:6.

Mole of 84.0 g glucose = 84/180.156 = 0.4662 moles

Equivalent mole of water = 0.4662 x 6 = 2.7975 moles

Mass of 2.7975 moles water = 2.7975 x 18 = 50.36 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

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