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Over [174]
2 years ago
12

Why is the combined gas law the most practiced gas law

Chemistry
2 answers:
vfiekz [6]2 years ago
8 0
The combined gas law allows you to derive any of the relationships needed by combining all of the changeable peices in the ideal gas law: namely pressure, temperature and volume
rjkz [21]2 years ago
3 0

The combined gas law allows you to derive any of the relationships needed by combining all of the changeable peices in the ideal gas law: namely pressure, temperature and volume.
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21.7 mL of gas at 98.8 kPa is allowed to expand at constant
IRISSAK [1]

Answer: 40.68 kPa

Explanation:

Given that,

Original volume of gas V1 = 21.7 mL

Original pressure of gas P1 = 98.8 kPa

New volume of gas V2 = 52.7 mL

New pressure of gas P2 = ?

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

98.8 kPa x 21.7 mL = P2 x 52.7L

2143.96 kPa L = 52.7 L x P2

P2 = 2143.96 kPa L / 52.7 L

P2 = 40.68 kPa

Thus, the new pressure of the gas is 40.68 kPa.

5 0
3 years ago
The film used to take pictures is coated with?
Naddika [18.5K]

The film which you called it is photographic film and it is strip like sheet and it's surface is clrear and transparent plastic which is coated on

two sided one side is with gelatin emulsion consists microscopic small light-sensor which is actually very sensitive in nature silver halides crystals. The size shape and other characters of the crystals gives the sensitivity,contrast of different colors combination ,and resolution of the films.

6 0
3 years ago
Using the graph below please draw a reaction potential energy diagram for a reaction with the
azamat

Answer:

12

Explanation:

because it is the sam

7 0
3 years ago
What is the percent by mass of Fluorine in Nitrogen triflouride NF3?
Kipish [7]

Answer:

The answer to your question is 80.3%

Explanation:

Data

Percent by mass of F

molecules NF₃

Process

1.- Calculate the molar mass of nitrogen trifluoride

molar mass = (1 x 14) + (19 x 3)

                    = 14 + 57

                    = 71 g

2.- Use proportions and cross multiplications to find the percent by mass of F. The molar mass of NF₃ is equal to 100%.

                       71 g of NF₃ ------------------ 100%

                       57 g of F   ------------------- x

                            x = (57 x 100)/71

                            x = 5700 / 71

                            x = 80.3%

3.- Conclusion

Fluorine is 80.3% by mass of the molecule NF₃

           

3 0
3 years ago
Draw the structure of bromous acid, hbro2. optimize formal charges.
ArbitrLikvidat [17]

STRUCTURE OF BROMOUS ACID: H–O–Br=O

<span>In this structure, all the elements have a formal charge of zero. The formal charge of each element is calculated below: </span><span>

H: 1 – 1/2(2) – 0 = 0
O: 6 – 1/2(4) – 4 = 0
Br: 7 – 1/2(6) – 4 = 0
<span>O: 6 – 1/2(4) – 4 = 0</span></span>

8 0
3 years ago
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