A molecule of composition is replicated in a solution containing unlabeled (not radioactive) GTP, CTP, and TTP plus adenine nucl
1 answer:
Answer:
Please find the complete question in the attached file.
Explanation:
It would only be radioactive if the DNA molecule that employed the poly-T rand as templates. Its other molecule of the daughter would not have been radioactive as it did not need dATP for its replication. While each strand of the second molecule includes t, simultaneous reproduction dATP from both daughter molecules is needed so that each of those is radioactive.
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Answer:
Moles of potassium chlorate reacted = 0.2529 moles
The amount of oxygen gas collected will be 12.8675 g
Explanation:
(a)
We are given:
Vapor pressure of water = 17.5 mmHg
Total vapor pressure = 748 mmHg
Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (748 - 17.5) mmHg = 730.5 mmHg
To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 730.5 mmHg
V = Volume of the gas = 9.49 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
According to the reaction shown below as:-
3 moles of oxygen gas are produced when 2 moles of potassium chlorate undergoes reaction.
So,
0.3794 mol of oxygen gas are produced when moles of potassium chlorate undergoes reaction.
<u>Moles of potassium chlorate reacted = 0.2529 moles</u>
(b)
We are given:
Vapor pressure of water = 17.5 mmHg
Total vapor pressure = 753 mmHg
Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (753 - 17.5) mmHg = 735.5 mmHg
To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 735.5 mmHg
V = Volume of the gas = 9.99 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
Moles of Oxygen gas = 0.40211 moles
Molar mass of Oxygen gas = 32 g/mol
Putting values in above equation, we get:
<u>Hence, the amount of oxygen gas collected will be 12.8675 g</u>
The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.
Further Explanation:
To solve this problem, follow the steps below:
- Write the balanced chemical equation for the given reaction.
- Convert the mass of calcium carbonate into moles.
- Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
- Convert the number of moles of calcium oxide into mass.
Solving the given problem using the steps above:
STEP 1: The balanced chemical equation for the given reaction is:
STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.
STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.
For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,
STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.
Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.
Therefore,
Learn More
- Learn more about stoichiometry brainly.com/question/12979299
- Learn more about mole conversion brainly.com/question/12972204
- Learn more about limiting reactants brainly.com/question/12979491
Keywords: thermal decomposition, stoichiometry