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salantis [7]
3 years ago
13

Which of these is the largest quantity?

Chemistry
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

I would have to say the United States debt.

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Every conversion factor is a ratio that is<br> equal to 1<br> less than 1<br> greater than 1
miss Akunina [59]

equal to 1

Explanation:

All conversion factors used in any calculation is usually a ratio that is equal to 1. This is because when 1 is used to multiply or divide any number, the number stays the same.

  • Conversion factors are useful in making the simplification of an expression very simple. They are usually ratios of 1.
  • It follows that a conversion factor is a number that when multiplied or divided by itself will stay the same.

Learn more:

conversion factor: brainly.com/question/555814

#learnwithBrainly

4 0
3 years ago
Calcium oxide and oxygen gas are produced by the thermal decomposition of limestone in the reaction CaCO (s) CaO(s) + CO (g). Wh
kozerog [31]
The mass of lime that  can  be produced  from  4.510 Kg of limestone  is calculated  as  below

calculate the moles  of CaCO3  used

that is  moles =mass/molar mass
convert  Kg  to g  = 4.510 x1000 =4510g
=  4510 / 100 =45.10 moles
CaCO3 = CaO  +O2

by use of mole ratio between CaCO3  to CaO  (1:1) the  moles of CaO  is also= 45.10 moles
mass of CaO = moles x molar  mass

45.10  x56 = 2525.6  g  of  CaO



6 0
3 years ago
Read 2 more answers
Calculate the mass of carbon dioxide produced from complete combustion of 16.6 g of octane, C8H18, in the following reaction. C8
Oksi-84 [34.3K]

Answer:

51.2g of CO2

Explanation:

The first step is to balance the reaction equation as shown in the solution attached. Without balancing the reaction equation, one can never obtain the correct answer! Then obtain the masses of octane reacted and carbon dioxide produced from the stoichiometric equation. After that, we now compare it with what is given as shown in the image attached.

7 0
3 years ago
In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi
mart [117]

The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>
  • Molarity of acid, HCOOH (Ma) = 0.4 M
  • Volume of acid, HCOOH (Va) = 50 mL
  • Molarity of base, LiOH (Mb) = 0.15 M
  • Volume of base, LiOH (Vb) =?

MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

Divide both side by 0.15

Vb = 20 / 0.15

Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

Learn more about titration:

brainly.com/question/14356286

8 0
2 years ago
The pH of a basic solution is 9.77. What is [OH⁻]?
uysha [10]

The  [OH⁻] of the solution is 5.37×10⁵ M.

<h3 /><h3>What is pOH?</h3>

This is the negative logarithm to base 10 of hydroxy ion [OH⁻] concentration.

To calculate the hydroxy ion [OH⁻] concentration we use the formula below.

Note:

  • pH+pOH = 14
  • pOH = 14-pH
  • pOH = 14-9.77
  • pOH = 4.27

Formula:

  • [OH⁻] = 1/10^{pOH}................. Equation 1

Given:

  • pOH = 4.27

Substitute the value into equation 1

  • [OH⁻] = 1/10^{4.27}
  • [OH⁻]  = 5.37×10⁵

Hence, The [OH⁻] of the solution is 5.37×10⁵ M.

Learn more about hydroxy ion concentration here: brainly.com/question/17090407

7 0
2 years ago
Read 2 more answers
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