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PilotLPTM [1.2K]
2 years ago
10

Water is being heated in a closed pan on top of a range while being stirred by a paddle wheel.

Physics
1 answer:
BigorU [14]2 years ago
6 0

Heat transfer in a closed system is the addition of changes in internal energy and the total amount of work done by it.  The final energy of the system is 35.5kJ.  

<h3>What is heat transfer? </h3>

Heat transfer is the transfer of heat energy due to temperature differences.

The paddle-wheel paintings are quantities of workdone, 500 N.m or 0.5kJ.

The preliminary (initial) power of the device is 10 kJ.

Total warmness transferred in the course of the method is 30 kJ

Total warmness misplaced in the course of the method to the encompassing air is 5 kJ.

The energy of the system is given as:

The energy of the system = Energy in - Energy out

The energy of the system = Initial energy + Energy transferred + Work done - Energy lost

Energy of the system = 10 + 30 + 0.5 - 5 kJ

Energy of the system = 35.5 kJ

Read more about energy:

brainly.com/question/13881533

#SPJ1

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This diagram shows how a certain type of precipitation is formed. Water drops are caught in up-drafts and down-drafts, over and
Svet_ta [14]

It would be B. Hail.

5 0
4 years ago
PLEASE HELP!!!
d1i1m1o1n [39]

Answer: 95.7 N

Explanation: The tension on the chandelier is equal to the its weight.

Weight is the force directed downwards and tension is the force exerted of the opposite side.

T = W of the chain + W of the chandelier

  = m1( g) + m2 (g)

  = 0.37 kg ( 9.8 m/s2) + 9.4 kg (9.8 m/s2)

  = - 95.7 N  it means the force is directed downwards

since tension is equal weight

T = 95.7 N

6 0
3 years ago
A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .if after the collision it moves with a velocity of 2
ch4aika [34]

Answer:

-1.2 kg - m/s

Explanation:

\pink{\frak{Given}}\begin{cases}\textsf{ A body of mass 100g moving with a velocity of 10.0m/s collides with a wall .}\\\textsf{ After the collision it moves with a velocity of 2.0m/s in the opposite direction.}\end{cases}

And we need to find out the change in momentum of the body . Here ,

  • velocity before collision (u) = 10m/s
  • velocity after collision (v) = 2m/s .

We know that momentum is defined as amount of motion contained in a body . Mathematically ,

\sf\longrightarrow momentum (p)= mass(m) * velocity(v)

Therefore change in momentum will be,

\sf\longrightarrow \triangle p = mv - mu

Since the direction of velocity changes after the collision , the velocity will be -2m/s .

\sf\longrightarrow \Delta p = 100g( -2m/s -10m/s) \\

\sf\longrightarrow \Delta p =\dfrac{100}{1000}kg ( -12m/s)  \\

\sf\longrightarrow \Delta p   = 0.1 kg * -12m/s \\

\sf\longrightarrow \boxed{\bf \Delta p = -1.2 \ kg-m/s} \\

7 0
2 years ago
*PLEASE HELP WILL GIVE BRAINLIEST*
levacccp [35]

Answer: The order is 2,1,5,4,3

Explanation: Hope This helps.

3 0
3 years ago
Calculate the angular velocity and linea­r velocity of both wheels assuming the l­arger wheel rotates at 120 revolutions p­er mi
IRINA_888 [86]
<span>120 revolutions p­er min is (20RPM)
120revolutions is 240 Pi radians (because 1 revolution is 2Pi rad)

angular velocity
w= 240Pixf, f is the frequency and f= 1/T, T =1mn=60s=period, so f=1/60=0.01Hz
so w = 240*Pi*0.01=12.56 rad /s
linear velocity can be found with
V =Rx w,    
V=12.56 R the value depends on what value is the radius of both wheels

</span>
6 0
3 years ago
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