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Sedbober [7]
3 years ago
10

The ancient Egyptians build their pyramids using a ramp to move the heavy blocks up. The length of the ramp was 25m and the heig

ht was 10m the weight of the block was 250kg and the effort weight is 180kg. What is the efficiency of the inclined plane
Physics
1 answer:
hammer [34]3 years ago
5 0

Answer:

Efficiency of the inclined plane is 56%

Explanation:

efficiency = (work output / work input) x 100%

efficiency = ([load force x load distance] x [effort force x effort distance]) x 100%

efficiency = (250 kg x 10 m) / (180 kg x 25 m) x 100%

efficiency = (2500kg/m) / (4500kg/m) x 100%

efficiency = 0.555 = 0.56 x 100%

efficiency = 56%

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If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb'
Vitek1552 [10]

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge q= 10^{-6}\ C

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

F = \dfrac{kq_{1}q_{2}}{r^2}

Where, q = charge

r = distance

F = force

Put the value into the formula

1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}

r=\sqrt{9\times10^{9}\times(-10^{-6})^2}

r=0.095\ m

r= 9.5\ cm

Hence, The distance between the charges is 9.5 cm

4 0
3 years ago
A6 kg bag of rice is on the top shelf at a grocery store.
netineya [11]

Answer:

<h2>117.6 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 6 × 9.8 × 2

We have the final answer as

<h3>117.6 J</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
Find the wavelength of a photon which has 500.0 eV of energy.
jekas [21]

Answer:

2.5 x 10⁻⁹ m

Explanation:

E = Energy of photon = 500 eV = 500 x 1.6 x 10⁻¹⁹ J

c = speed of photon = 3 x 10⁸ m/s

λ = wavelength of photon = ?

Energy of photon is given as

E = \frac{hc}{\lambda }

inserting the values

500\times 1.6\times 10^{-19} = \frac{(6.63\times 10^{-34})(3\times 10^{8})}{\lambda }

λ = 2.5 x 10⁻⁹ m

5 0
4 years ago
How are animals of the coniferous forest well adapted to long, cold winters?
skelet666 [1.2K]
They have thick body coverings
3 0
3 years ago
Part A What is the resistance of a 4.4 m length of copper wire 1.3 mm n diameter? The resistivity of copper is 1.68x 10-8 Ω-m Ex
Natalija [7]

Explanation:

It is given that,

Length of the copper wire, l = 4.4 m

Diameter of copper wire, d = 1.3 mm = 0.0013 m

Radius of copper wire, r = 0.00065 m

The resistivity of the copper wire, \rho=1.68\times 10^{-8}\ \Omega-m

We need to find the resistance of the copper wire. It is given by :

R=\rho\dfrac{l}{A}

R=1.68\times 10^{-8}\ \times \dfrac{4.4\ m}{\pi (0.00065)^2}

R =0.055 ohms

So, the resistance of the copper wire is 0.055 ohms. Hence, this is the required solution.

7 0
3 years ago
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