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Kipish [7]
1 year ago
11

True or False? If ab>0, then a>0, b>0 or a<0, b<0

Mathematics
2 answers:
Tatiana [17]1 year ago
7 0
It’s true good job for asking
pickupchik [31]1 year ago
6 0

Answer:

true

2. If ab = 0, then a = 0 or b = 0. This statement is true. It is a property of the real numbers which was stated in class

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7. Marco is making beaded bracelets. Each
stiks02 [169]

One way to find the least common multiple of two numbers is to first list the prime factors of each number.

8 = 2 x 2 x 2

Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.

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4 0
2 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
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