Oxygen, Nitrogen and Fluorine
Explanation:
In order to participate in a hydrogen bond, a hydrogen atom must be covalently bonded to one of the oxygen, nitrogen and fluorine.
- Hydrogen bonding is a type of dipole - dipole attraction between two specie.
- It is an intermolecular force of attraction.
- This bond type forms when hydrogen is bonded to a more electronegative atom.
- These atoms are oxygen, nitrogen and fluorine
- These species draws the electron shared more to themselves and leaves a partial positive charge on the hydrogen and a negative charge on them.
- The electrostatic force of attraction between the hydrogen of one molecule and the O/N/F of another molecule cause the formation of hydrogen bonds.
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Hydrogen bonding brainly.com/question/10602513
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All living organisms are composed of one or more cells. The cell is the basic unit of structure and organization in organisms. Cells arise from pre-existing cells.
The chemical symbol for sodium bicarbonate is NaHCO3. Its molar mass is 84 g/mol. In each of one mol of sodium bicarbonate their is one mole of carbon dioxide with the molar mass of 44 grams per mol. We determine the number of moles in 0.10 g of sodium bicarbonate.
n sodium bicarbonate = (0.10 g) / (84 grams / mol)
= 1.19 x 10-3 moles sodium bicarbonate
Therefore, there are also 1.19 x 10-3 moles of carbon dioxide.
We can use the magnification equation for this problem.
Magnification equation:
<em>hi/h0 = di/d0</em>
Where in <em>hi </em>: image size, <em>h0</em> : object size, <em>di </em>: image distance, <em>d0 </em>: object distance from mirror
So plugging in the given variables we will have the corresponding equation
0.1 m / 0.3 m = <em>di / </em>0.4 m
<em>di</em> = 0.1333333m
The generated image of the object is located 0.13 meters or 13 cm away from the mirror
