Question

The molecular formula for butane is C4H10. Determine the percent composition for

Answer 1

%Mass

Ar C = 12 g/mol, Mr C₄H₁₀ = 58 g/mol, Ar H = 1 g/mol

$\tt C=\dfrac{4.12}{58}\times 100\%=82.8\%\\\\H=100\%-82.8\%=17.2\%$

or

$\tt H=\dfrac{10.1}{58}\times 100\%= 17.2\%$