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mash [69]
1 year ago
11

15. When traveling through a smoke-filled area, a person must be able

Chemistry
1 answer:
maxonik [38]1 year ago
5 0

When traveling through a smoke-filled area, a person must be able to have distance of at least 4 feet in order to safely reach a fire exit. That is option C.

<h3>What is a smoke-filled area?</h3>

Smoke-filled area is an enclosed area that is filled with smoke gas that is usually made up of carbon monoxide.

The smoke-filled area is usually caused by

  • Fire out break

  • Burning of plastics or chemical products

  • Release of fuming gases.

When there is smoke-filled area die to fire out break, there are some guidelines to follow to safely reach the fire exit early enough.

The importance of these guidelines include the following:

  • enable rescuers to navigate a scene more quickly,

  • identify risks and hazards,

  • locate safety points,

  • determine the safest way in and out of a building, and

  • map out evacuation routes.

The affected individual should get down and crawl while taking short breath through the nose because cleaner air is nearest to the floor.

Learn more about distance here:

brainly.com/question/7243416

#SPJ1

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Hydroxyl radicals react with and eliminate many atmospheric pollutants. However, the hydroxyl radical does not clean up everythi
Nesterboy [21]

Answer:

ΔHreaction = 263.15 kJ/mol

Explanation:

The reaction is as follow:

OH + CF₂Cl₂ → HOF + CFCl₂

You need to calculate the enthalpy of reaction and for this it is necessary to know the standard enthalpies for each of the compounds. These enthalpies are as follows and can be found in your textbook or on the Internet.

ΔHreaction = ∑ΔHproducts - ∑ΔHreactants

delta(H)_{reaction} =((1*(-97.8)+(1*(-92))-((1*39)+(1*(-491.15))=263.15kJ/mol

7 0
2 years ago
At sea level the average heigh of mercury in barometer is
liubo4ka [24]
Although 1013.25 mb (760 mm Hg) is considered to be the standard atmospheric pressure at sea level, it does not mean that the pressure at this level has this value, actually this being 1011 mb.
4 0
3 years ago
How can constraints be used to help define the problem?
vitfil [10]

Answer:

Constraints are restrictions that need to be placed upon variables 

Explanation:

Constraints are restrictions (limitations, boundaries) that need to be placed upon variables used in equations that model real-world situations. It is possible that certain solutions which make an equation true mathematically, may not make any sense in the context of a real-world word problem.

6 0
3 years ago
4) Ethanol has a density of 0.8 g/cm3. <br> What is the mass of 225 cm3 of ethanol
AveGali [126]

Answer:

\huge\boxed{\sf m = 180\  g}

Explanation:

<u>Given:</u>

Density = ρ = 0.8 g/cm³

Volume = V = 225 cm³

<u>Required:</u>

Mass = m = ?

<u>Formula:</u>

m = ρV

<u>Solution:</u>

m = (0.8)(225)

m = 180 g

\rule[225]{225}{2}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
7 0
2 years ago
Predict whether or not a precipitate forms upon mixing 175.0 ml of a 0.0055 mkcl solution with 145.0 ml of a 0.0015 m agno3 solu
REY [17]

Step 1: Write down the chemical reaction

KCl(aq) + AgNO3(aq) → AgCl(s) + KNO3(aq)

The precipitate that can be expected is AgCl

Step 2: Calculate the moles of KCl and AgNO3

# moles of KCl = V(KCl) * M(KCl)

                        = 0.175 L * 0.0055 moles/L = 9.63*10⁻⁴ moles

# moles of AgNO3 = V(AgNO3) * M(AgNO3)

                        = 0.145 L * 0.0015 moles/L = 2.18*10⁻⁴ moles

Since moles of AgNO3 < KCl, the former is the limiting reagent

Therefore, moles of AgCl formed = 2.18*10⁻⁴ moles

Step 3: Predict if AgCl precipitate will be formed

The solubility product Ksp for AgCl = 1.6 *10⁻¹⁰

i.e.

AgCl(s) ↔ Ag⁺(aq) + Cl⁻(aq)

Ksp = [Ag+][Cl-]

if [Ag+][Cl-] > Ksp then precipitation will occur

Now total volume of the solution = 175 + 145 = 320 ml = 0.320 L

[Ag+] = [Cl-] = 2.18*10⁻⁴ moles/0.320 L = 6.81*10⁻⁴ M

[Ag+][Cl-] = (6.81*10⁻⁴)² = 4.64 *10⁻⁷

Since  [Ag+][Cl-] > Ksp, AgCl precipitate will be formed.


8 0
3 years ago
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