Answer:
1.005 cm³
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 0.650 cm³
V₂ = ?
P₁ = 1.54 atm
P₂ = 1.01 atm
T₁ = 12°C
T₂ = 16 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (12 + 273.15) K = 285.15 K
T₂ = (16 + 273.15) K = 289.15 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 1.005 cm³</u>
Yes as it is less dense than the liquid water
Answer:
1. Classical conditioning. Classical conditioning is a type of associative learning based on the association between a neutral stimulus with another that is significant for a person or an animal in order to generate a similar response.
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E=hv
=6.625×10^-34Js^-1×1.97×10^8s^-1
Cancel sec inverse.
=13.05×10^-26.
Hello!
The precipitate of the reaction that occurs <span>when a silver nitrate solution is mixed with a sodium chloride solution is silver chloride (AgCl).
The chemical equation for this precipitation reaction is the following:
AgNO</span>₃(aq) + NaCl(aq) → AgCl↓(s) + NaNO₃(aq)
Silver Chloride is a chemical compound that is poorly soluble in water because the chemical bond between Ag⁺ and Cl⁻ is very strong as the two ions are nearly the same size and have similar electronic densities. If the chemical bond is strong, it is more difficult for water molecules to break this bond to surround the individual ions, and thus solubility will decrease.
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