Question

Two moles of propene (c3h6) gas react with nine moles of oxygen (o2) gas to produce six moles of carbon dioxide gas (co2) and six moles of water gas (h2o). using this description of the reaction, write the corresponding chemical equation, showing the appropriate coefficients for each reactant and product. (include states-of-matter under the given conditions in your answer.)

Answer 1

The stoichiometry of the reaction gives the molar ratio in which the reactants react with each other and the ratio in which products are formed.
The coefficients of the reactants in the reaction follow the stoichiometry 
the balanced chemical equation for the reaction is as follows;
2C₃H₆(g) + 9O₂(g)  ---> 6CO₂(g) + 6H₂O(l)

Answer 2

Answer:

$2C_3H_6(g)+9O_2(g)-->6CO_2(g)+6H_2O(g)$

Explanation:

Hello,

In this case, based on the given description, the corresponding chemical reaction turns out into:

$2C_3H_6(g)+9O_2(g)-->6CO_2(g)+6H_2O(g)$

Wherein the numbers preceding the compound formula are referred to the stoichiometric coefficients and the $(g)$ to the gaseous state-of-matter at which the chemical reaction is carried out. Such coefficients are useful to respect the law of conservation of mass.

Best regards.